专家您好，我在从 SQL Server 进行更新查询时遇到问题。首先运行一个选择查询，然后将结果传递给 currentdb.execute（以更新当前使用的访问文件的表），使用 Access vba 我做得不对。我真的希望你能帮助我。也许你们知道更好的方法来运行我的程序：
- 连接到 sql server 2008，运行选择查询。
- 将 select 查询的结果传递给 access 数据库执行命令（或者如果您有更好的主意）以更新当前正在使用的 access 文件中的表。
我得到的代码错误是类型不匹配并突出显示.OpenSchema。
这些是我做错的代码的一部分（我真的不知道该怎么做）。
dbObj.Execute ("UPDATE ACCESS.tbl_Name RIGHT JOIN " & _
conn.OpenSchema(adSchemaTables, Array(Empty, Empty, Empty, "SQLSVR.tbl_Name")) & _
" ON ACCESS.tbl_Name.FieldName_access = " & rst!FieldName_sqlsvr & _
" SET ACCESS.tbl_Name.FieldName_access = " & rst!FieldName_sqlsvr)
这是整个代码。
Option Compare Database
Sub LocalSQLServerConn_Test()
Dim dbOjb As DAO.Database
Dim strDBName As String
Dim strUserName As String
Dim strPassword As String
Set dbObj = CurrentDb()
Set conn = New adodb.Connection
Set rst = New adodb.Recordset
strDBName = "DataSet"
strConnectString = "Provider = SQLOLEDB.1; Integrated Security = SSPI; " & _
"Initial Catalog = " & strDBName & "; Persist Security Info = True; " & _
"Workstation ID = ABCDE12345;"
conn.ConnectionString = strConnectString
conn.Open
strSQL = "SELECT DISTINCT SQLSVR.tbl_Name.FieldName_sqlsvr FROM SQLSVR.tbl_Name"
rst.Open Source:=strSQL, ActiveConnection:=conn, _
CursorType:=adOpenDynamic, LockType:=adLockOptimistic
If rst.RecordCount = 0 Then
MsgBox "No records returned"
Else
rst.MoveFirst
Do While Not rst.EOF
dbObj.Execute ("UPDATE ACCESS.tbl_Name RIGHT JOIN " & _
conn.OpenSchema(adSchemaTables, Array(Empty, Empty, Empty, "SQLSVR.tbl_Name")) & _
" ON ACCESS.tbl_Name.FieldName_access = " & rst!FieldName_sqlsvr & _
" SET ACCESS.tbl_Name.FieldName_access = " & rst!FieldName_sqlsvr)
rst.MoveNext
Loop
End If
conn.Close
rst.Close
Set dbObj = Nothing
End Sub