3

我正在尝试使用 javascript 验证表单。该函数被正确调用并显示警报，但在我单击警报后仍提交表单。该函数永远不会返回 false。我以前看过这个问题，但我还没有看到有效的答案。我在其中使用了一些 JQuery 移动设备，这可能是问题所在。我试图改变按钮输入类型=按钮，但这甚至不会提交表单。

javascript函数是：

<script>
function validateInventoryform()
{
var sku=document.getElementById('sku_checkbox');
var entire=document.getElementById('entire_checkbox');
var inv=document.getElementById('inv');
if ((sku.checked==true && entire.checked==true))
 {
alert("You may only choose one option to check customer inventory");
return false;
 }
}
</script>

表格是：

<div data-role="popup" id="popupQuery_inventory" data-theme='a' > 
  <div style="padding:10px 20px;">
    <form action="inventory_inquiry.php" method="get" id="inv" onsubmit="return validateInventoryform()" >           
     <h3>Enter SKU</h3>
      <fieldset data-role="controlgroup" data-type="horizontal" data-mini="true">
        <legend>Choose Input Type:</legend>
          <input type="checkbox" data-theme="a" name="sku_checkbox" id="sku_checkbox" value="off" checked="checked">
          <label for="sku_checkbox">SKU</label>
          <input type="checkbox" data-theme="a" name="entire_checkbox" id="entire_checkbox" value="off">
         <label for="entire_checkbox">Entire Inventory</label>
         </fieldset>

            <label for="sku" class="ui-hidden-accessible">SKU:</label>
            <input type="text" name="sku" id="sku" value="" placeholder="Item SKU" data-theme="a">
            <input name="customer_id" type="hidden" value='<?php echo $customer_id; ?>'/>
           <button type="submit" data-theme="b"/>Submit</button>
        </form>    
   </div>
</div>

我正在添加调用表单弹出窗口的 href。我不知道这是否与这个问题有关。我一直听说我的代码正在被复制并且运行良好。我无法让它工作，我想完整地代表这个问题。

<ul data-role="listview" data-inset="true" data-theme="b">
    <li><a href="#popupCustomer_alert" data-rel="popup" data-position-to="origin" data-inline="true" data-transition="pop" >Add Customer Alert</a></li>
    <li><a href="#popupQuery_inventory" data-rel="popup" data-position-to="origin" data-inline="true" data-transition="pop" >Query Inventory</a></li>
    <li><a href="#popupEdit_customer" data-rel="popup" data-position-to="origin" data-inline="true" data-transition="pop" >Edit Customer</a></li>
    <li><a href="return_qr_code.php" >Get QR Code</a></li>
    <li><a href="#popupDownload_inventory" data-rel="popup" data-position-to="origin" data-inline="true" data-transition="pop" >Download Inventory</a></li>
</ul>
4

5 回答 5

0

尝试在 validateInventoryform() 的最后一行添加 return true 并删除额外的“/”

 <button type="submit" data-theme="b"/>Submit</button>

尝试 Jquery 绑定事件

$(function () {
        $('#form').bind('submit', function (e) {
            var isValid = true;
            if (!isValid) {
                e.preventDefault();
            }
        });
    });
于 2013-06-20T05:15:17.003 回答
0

最好在提交之前验证表单。对按钮单击进行验证。

或者更好的是，使用单选按钮而不是复选框，因为您只想允许选择一个选项：

<input type="radio" data-theme="a" name="input_type" id="sku_checkbox" value="SKU" />
<input type="radio" data-theme="a" name="input_type" id="entire_checkbox" value="Entire Inventory" />
于 2013-06-20T05:18:56.153 回答
0

下面的编码工作完美：

<html>
    <head>
        <title>checkbox</title>
        <script type="text/javascript">
            function validateInventoryform()
 {
var sku=document.getElementById('sku_checkbox');
var entire=document.getElementById('entire_checkbox');
var inv=document.getElementById('inv');
if ((sku.checked==true && entire.checked==true))
 {
alert("You may only choose one option to check customer inventory");
return false;
 }
}
        </script>
    </head>
<body>
    <div data-role="popup" id="popupQuery_inventory" data-theme='a' > 
  <div style="padding:10px 20px;">
    <form action="inventory_inquiry.php" method="get" id="inv" onsubmit="return validateInventoryform()" >           
     <h3>Enter SKU</h3>
      <fieldset data-role="controlgroup" data-type="horizontal" data-mini="true">
        <legend>Choose Input Type:</legend>
          <input type="checkbox" data-theme="a" name="sku_checkbox" id="sku_checkbox" value="off" checked="checked">
          <label for="sku_checkbox">SKU</label>
          <input type="checkbox" data-theme="a" name="entire_checkbox" id="entire_checkbox" value="off">
         <label for="entire_checkbox">Entire Inventory</label>
         </fieldset>

            <label for="sku" class="ui-hidden-accessible">SKU:</label>
            <input type="text" name="sku" id="sku" value="" placeholder="Item SKU" data-theme="a">
            <input name="customer_id" type="hidden" value='<?php echo $customer_id; ?>'/>
           <button type="submit" data-theme="b"/>Submit</button>
        </form>    
   </div>
</div>

</body>


</html>
于 2013-06-20T05:32:16.430 回答
0

试试这个，我希望这就是你要找的：

html:

<div data-role="popup" id="popupQuery_inventory" data-theme='a' > 
  <div style="padding:10px 20px;">
    <form action="inventory_inquiry.php" method="get" id="inv">           
     <h3>Enter SKU</h3>
      <fieldset data-role="controlgroup" data-type="horizontal" data-mini="true">
        <legend>Choose Input Type:</legend>
            <input type="radio" data-theme="a" name="input_type" id="sku_checkbox" value="SKU" />SKU
            <input type="radio" data-theme="a" name="input_type" id="entire_checkbox" value="Entire Inventory" />Entire Inventory
         </fieldset>

            <label for="sku" class="ui-hidden-accessible">SKU:</label>
            <input type="text" name="sku" id="sku" value="" placeholder="Item SKU" data-theme="a" />
            <input name="customer_id" type="hidden" value='<?php echo $customer_id; ?>'/>
            <input type="button" data-theme="b" value="Submit" id="submitBtn" />
        </form>    
   </div>
</div>

Javascript

$("#submitBtn").on("click", function(event){
    //Your validation code here
    if($("#sku").val() == ""){
        alert("Item sku is null")
    } else {
        // Submit event if everything is okey
        $("#inv").submit();
    }
});

http://jsfiddle.net/8aapR/

于 2013-06-20T06:53:46.393 回答
0

我正在使用您提供的相同 html 和脚本代码，并在所有浏览器中进行了测试，并且运行良好。

<html>
    <head>
        <script>
    function validateInventoryform()
    {
    var sku=document.getElementById('sku_checkbox');
    var entire=document.getElementById('entire_checkbox');
    var inv=document.getElementById('inv');
    if ((sku.checked==true && entire.checked==true))
     {
    alert("You may only choose one option to check customer inventory");
    return false;
     }
    }
    </script>
    </head>
    <body>
    <div data-role="popup" id="popupQuery_inventory" data-theme='a' > 
      <div style="padding:10px 20px;">
        <form action="inventory_inquiry.php" method="get" id="inv" onsubmit="return validateInventoryform()" >           
         <h3>Enter SKU</h3>
          <fieldset data-role="controlgroup" data-type="horizontal" data-mini="true">
            <legend>Choose Input Type:</legend>
              <input type="checkbox" data-theme="a" name="sku_checkbox" id="sku_checkbox" value="off" checked="checked">
              <label for="sku_checkbox">SKU</label>
              <input type="checkbox" data-theme="a" name="entire_checkbox" id="entire_checkbox" value="off">
             <label for="entire_checkbox">Entire Inventory</label>
             </fieldset>

                <label for="sku" class="ui-hidden-accessible">SKU:</label>
                <input type="text" name="sku" id="sku" value="" placeholder="Item SKU" data-theme="a">
                <input name="customer_id" type="hidden" value='<?php echo $customer_id; ?>'/>
               <button type="submit" data-theme="b"/>Submit</button>
            </form>    
       </div>
    </div>
    </body>
    </html>
于 2013-06-20T10:57:10.660 回答