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我不知道如何显示管理员(医生)每天观看的用户(患者)数量。我有这份每日报告,可以打印我每天的总销售额,但如果我需要显示数量用户(pacientes)他看到(如 10 个 pacientes)代码打印 2000 或更多..

你能帮我解决这个问题吗?

<table class="table table-bordered table-striped table-condensed">
    <thead>
        <tr>
          <th>Fecha</th>
          <th>Total Pacientes vistos</th>
          <th>Total diario</th>                                 
        </tr>
    </thead>   
    <tbody>
        <tr>
            <? 
                include 'config.php';
                $sql = $conn->prepare("SELECT DATE(start) AS date, SUM(id_paciente) AS total_pacientes, SUM(honorario) AS total_diario
                FROM CITAS WHERE start >= CURDATE() AND start < CURDATE() + INTERVAL 1 DAY ORDER BY start ASC");
                $sql->execute();
                while($row = $sql->fetch(PDO::FETCH_ASSOC)) {
            ?>
            <td class="center"><? echo $row['date']; ?></td>
            <td class="center"><? echo $row['total_pacientes']; ?></td>
            <td class="center"><? echo $row['total_diario']; ?></td>                 
        </tr>   <? } ?>                          
    </tbody>
</table> 

表 CITAS

  • 开始 日期时间
  • Honorario varchar
  • id_paciente int

我需要这样的报告显示:

date(fecha)--------total_user(total de pacientes)-----total_sales(total diario)

  • 10-junio-2013----------25---------------------------------650.00
  • 09-junio-2013----------10---------------------------------250.00
  • 08-junio-2013----------15---------------------------------375.00

但现在显示它是这样的:

date(fecha)--------total_user(total de pacientes)-----total_sales(total diario)

  • 10-junio-2013---------65725---------------------------------650.00
  • 09-junio-2013----------34510---------------------------------250.00
  • 08-junio-2013----------49815---------------------------------375.00

id_paciente 有 17,000 个用户,是表 PACIENTES 的 FK

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1 回答 1

1

问题是这样的:

SUM(id_paciente) AS total_pacientes

您不想对 id 求和。你想数一数。将其替换为:

count(id_paciente) AS total_pacientes
于 2013-06-20T00:59:18.307 回答