我正在使用 MySql 和 Nodejs。我需要存储一个仅由 0 和 1 组成的巨大字符串。（这是一个地图网格。0 = 可以移动，1 = 不能移动。）
Ex: 00000000000000000000000000000000000010000000000000000000000010000000000000000000000000000000000000000000000000000000000000000000000100000000000000000000000100000000000000000000000000000000000000000000000000000000000000000000001000000000000000000000001000000000000000000000000000000000000000000000000000000000000000000000010000000000 ...
我应该把那个字符串编码成base64字符串并以这种方式存储吗？然后当我需要它时，我解码它？如果是这样，我将如何使用 Nodejs/Javascript？
谢谢
您存储的数据似乎很容易压缩，为什么不使用内置的 MySql COMPRESS功能
生的：
mysql> select length('00000000000000000000000000000000000010000000000000000000000010000000000000000000000000000000000000000000000000000000000000000000000100000000000000000000000100000000000000000000000000000000000000000000000000000000000000000000001000000000000000000000001000000000000000000000000000000000000000000000000000000000000000000000010000000000');
332
使用压缩
mysql> select length(compress('00000000000000000000000000000000000010000000000000000000000010000000000000000000000000000000000000000000000000000000000000000000000100000000000000000000000100000000000000000000000000000000000000000000000000000000000000000000001000000000000000000000001000000000000000000000000000000000000000000000000000000000000000000000010000000000'));
23
不要存储字符串，存储二进制文件。
这是一个可以将该数据转换为二进制的方法示例。希望您可以重新设计事物，以便您的地图数据从一开始就永远不会表示为字符串。
static void Main(string[] args)
{
const string data =
"00000000000000000000000000000000000010000000000000000000000010000000000000000000000000000000000000000000000000000000000000000000000100000000000000000000000100000000000000000000000000000000000000000000000000000000000000000000001000000000000000000000001000000000000000000000000000000000000000000000000000000000000000000000010000000000";
var arrayLength = data.Length/8;
if (data.Length%8 != 0)
arrayLength++;
var binaryData = new byte[arrayLength];
byte nextByte=0;
var k = -1;
for (var i = 0; i < data.Length; i++)
{
var j = i%8;
if (j == 0)
{
binaryData[++k] = nextByte;
nextByte = 0;
}
var bit = int.Parse(data[i].ToString());
if(bit==1)
nextByte |= (byte)(bit << j);
}
binaryData[k] = nextByte;
}