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from google.appengine.ext import blobstore
upload_url = blobstore.create_upload_url('/upload')

uplaod_url 是一个唯一的 url,如何在处理程序中获取它?

from google.appengine.ext.webapp import blobstore_handlers
class UploadHandler(blobstore_handlers.BlobstoreUploadHandler):
  def post(self):
    upload_files = self.get_uploads('file')
    blob_info = upload_files[0]
    self.redirect('/serve/%s' % blob_info.key())
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1 回答 1

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您不希望它在 post 处理程序中。在文件已上传后调用,但上传本身由 App Engine 内部处理。

于 2013-06-19T08:28:54.580 回答