1

我有以下查询，当前返回 2 行（它总是只返回 2 行）。

Select
    User_Profile.userid, User_Profile.displayname, User_Profile.picPath,
    Battle.id as battleid, Battle.challenger_id as challengerid,
    Video.[filename]
From 
    Battle
INNER Join  
    User_Profile ON Battle.challenger_id = User_Profile.userid OR
                    Battle.challenged_id = User_Profile.userid
INNER Join
    Video ON User_Profile.userid = Video.[user_id]
WHERE
    Video.battle_id = Battle.id

这将返回如下内容：

userid | displayname | picPath  | battleid | challengerid | filename
--------------------------------------------------------------------
6      | CandyPoo   | test.jpg  |   12     | 9            | test.mp4
9      | Nawlrus    | test2.jpg |   12     | 9            | test2.mp4

我希望返回这样的东西：

battleid | challengerid | xuserid | xdisplayname | xpicPath  | xfilename | Yuserid | YdisplayName | YpicPath | YfileName
--------------------------------------------------------------------------------------------------------------------------
12       | 9            |  9      | Nawlrus      | test2.jpg | test2.mp4 | 6       | CandyPoo     | test.jpg | test.mp4

有没有办法做到这一点？我将返回多行，如上面的行（Top X），但需要合并具有相同battleid 的行，如您在上面看到的表格。这在 SQL Server 2008 中可行吗？

4

2 回答 2

1

您说您的查询将始终只返回两行。如果确实如此，那么您可以使用row_number()为每一行分配一个序列值，然后使用带有 CASE 表达式的聚合函数将行转换为列：

select battleid,
  challengerId,
  max(case when seq = 1 then userid end) xUserId,
  max(case when seq = 1 then displayname end) xDisplayName,
  max(case when seq = 1 then picPath end) xPicPath,
  max(case when seq = 1 then filename end) xFileName,
  max(case when seq = 2 then userid end) yUserId,
  max(case when seq = 2 then displayname end) yDisplayName,
  max(case when seq = 2 then picPath end) yPicPath,
  max(case when seq = 2 then filename end) yFileName
from
(
  Select User_Profile.userid, 
    User_Profile.displayname, 
    User_Profile.picPath,
    Battle.id as battleid, 
    Battle.challenger_id as challengerid,
    Video.[filename],
    row_number() over(partition by battle.id order by user_profile.userid) seq
  From Battle
  INNER Join User_Profile 
    ON Battle.challenger_id = User_Profile.userid 
    OR Battle.challenged_id = User_Profile.userid
  INNER Join Video 
    ON User_Profile.userid = Video.[user_id]
    AND Video.battle_id = Battle.id
) src
group by battleid, challengerId
于 2013-06-19T04:07:03.083 回答
0

您可以执行类似于下面的操作，在其中声明初始选择，然后将其重新加入，您可以在其中区分用户 ID

;with
    GetData as
    (
        Select
        User_Profile.userid as userid, User_Profile.displayname as displayname
            ,User_Profile.picPath as picpath,
        Battle.id as battleid, Battle.challenger_id as challengerid,
        Video.[filename] as vfilename
        From Battle
        INNER Join  
        User_Profile ON Battle.challenger_id = User_Profile.userid OR
        Battle.challenged_id = User_Profile.userid
        INNER Join
        Video ON User_Profile.userid = Video.[user_id]
        WHERE
        Video.battle_id = Battle.id
    )
    SELECT battleid, challengerid
           ,a.userid as xuserid, a.displayname as xdisplayname, a.picpath as xpicpath
           ,a.vfilename as xfilename
           ,b.userid as yuserid, b.displayname as ydisplayname, b.picpath as ypicpath
           ,b.vfilename as yfilename
    FROM GetData a
    JOIN GetData b on a.battleid = b.battleid and a.userid != b.userid
于 2013-06-19T04:03:49.193 回答