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奇怪的是，我找不到这个问题的答案，但是，我收到了这个错误：

TypeError: 'undefined' is not a function (evaluating 'i.replace(et,"<$1></$2>")')

它似乎来自这行代码（我不得不煞费苦心地注释每一行代码才能找到它）：

$.post("include/ajax.php", {updateWorkArt:"1", title:title, height:height, width:width, medium:medium, type:type, id:id, left:fin, top:top}, function(data){},"json");

这是完整的代码：

$(document).on("click", "#updateWorkPopup", function(){
        var title = $("#updateWorkTitle").val();
        var height = $("#updateWorkHeight").val();
        var width = $("#updateWorkWidth").val();
        var medium = $("#updateWorkMedium").val();
        var type = $("#updateWorkAssetType").val();

        var id = $("#whiteBgPopup").attr("data-workid");

        if($.trim(title) != "" && $.trim(height) != "" && $.trim(width) != "" && $.trim(medium) != "" && $.trim(type) != "")
        {
            var left = parseInt($("#offsetContainer").position().left);

            var containerMid = parseInt($(window).width()/2);

            var fin = (-containerMid+left)*-1;

            var top = parseInt($("#wall").height()/2);

            $.post("include/ajax.php", {updateWorkArt:"1", title:title, height:height, width:width, medium:medium, type:type, id:id, left:fin, top:top}, function(data){
                if(data.success)
                {   
                    $("#popUp").fadeOut("slow", function(){
                        $("#popUp").find("input").each(function(){
                            $(this).val("").blur();
                        });

                        $("#wall").append("<div class='adjustArtwork' data-workid='" + id + "' style='left:" + fin + "px; top:" + top + "px;' ><img src='" + data.image + "' width='" + data.width + "' /></div>", function(){
                            alert("finished");
                        });
                    });
                }
                alert("yes!");
            },"json");
        }
    });

这个错误到底是什么意思？

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2 回答 2

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这意味着（很可能）您的变量i引用了一个没有名为replace.

当你要求

i.replace

JavaScript 查找 的值，i发现它是一个对象；然后查找它的replace属性并没有找到它，所以它返回了undefined。

然后它尝试i.replace作为函数调用，但“未定义不是函数”。

It is also possible that the value of i.replace actually was the value undefined (though this is rare and added only for completeness).

In either case, the code

i.replace(et,"<$1></$2>")

only works if the value of i.replace is a function.

于 2013-06-19T02:18:59.897 回答
0

I found the problem.

It appears that .append() does not have a callback function and was causing an error because it is undefined.

Thankfully though, .append() is synchronous so my code will load in the order it is written; no function() is needed.

于 2013-06-20T13:33:26.700 回答