我有一个用 C# 构建的 WCF RESTful(即 JSON)服务。DataContract 方法之一可以返回非常大的响应,最小 10 MB,最大可能超过 30 MB。它都是文本,并将其作为 JSON 数据返回给客户端。当我在浏览器中测试这个方法时,我看到它超时了。我知道有一种方法可以压缩 WCF RESTful 服务响应数据。由于互操作性对我的目的来说绝对是至关重要的,是否仍然可以压缩 WCF RESTful 服务响应数据?现在,我仍在本地机器上测试该项目。不过,我会将其部署到 IIS。
如果有一种方法可以通过互操作性进行压缩,那么如何做到这一点?
谢谢你。
这实际上不是我正在使用的文件集,但它只是一个示例,展示了我如何构建我的服务。我意识到这个样本根本不需要压缩。
IService1.cs:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Runtime.Serialization;
using System.ServiceModel;
using System.ServiceModel.Web;
using System.Text;
namespace WcfService4
{
// NOTE: You can use the "Rename" command on the "Refactor" menu to change the interface name "IService1" in both code and config file together.
[ServiceContract]
public interface IService1
{
[OperationContract]
[WebInvoke(
Method = "GET",
UriTemplate = "employees",
RequestFormat = WebMessageFormat.Json,
ResponseFormat = WebMessageFormat.Json,
BodyStyle = WebMessageBodyStyle.Bare)]
List<Employee> GetEmployees();
}
// Use a data contract as illustrated in the sample below to add composite types to service operations.
[DataContract]
public class Employee
{
[DataMember]
public string FirstName { get; set; }
[DataMember]
public string LastName { get; set; }
[DataMember]
public int Age { get; set; }
public Employee(string firstName, string lastName, int age)
{
this.FirstName = firstName;
this.LastName = lastName;
this.Age = age;
}
}
}
服务1.svc.cs:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Runtime.Serialization;
using System.ServiceModel;
using System.ServiceModel.Web;
using System.Text;
using System.Net;
namespace WcfService4
{
// NOTE: You can use the "Rename" command on the "Refactor" menu to change the class name "Service1" in code, svc and config file together.
public class Service1 : IService1
{
public List<Employee> GetEmployees()
{
// In reality, I'm calling the data from an external datasource, returning data to the client that exceeds 10 MB and can reach an upper limit of at least 30 MB.
List<Employee> employee = new List<Employee>();
employee.Add(new Employee("John", "Smith", 28));
employee.Add(new Employee("Jane", "Fonda", 42));
employee.Add(new Employee("Brett", "Hume", 56));
return employee;
}
}
}