4

是否可以捕获发生在屏幕上的所有事件/错误/日志console并将它们显示在屏幕上的元素中?这可以用 JavaScript 完成吗?

4

3 回答 3

4

您始终可以覆盖这些console方法,也可以点击window'serror事件。这是一个覆盖的示例,包括监听error事件。

(function () {
    "use strict";

    var methods, generateNewMethod, i, j, cur, old, addEvent;

    if ("console" in window) {
        methods = [
            "log", "assert", "clear", "count",
            "debug", "dir", "dirxml", "error",
            "exception", "group", "groupCollapsed",
            "groupEnd", "info", "profile", "profileEnd",
            "table", "time", "timeEnd", "timeStamp",
            "trace", "warn"
        ];

        generateNewMethod = function (oldCallback, methodName) {
            return function () {
                var args;
                alert("called console." + methodName + ", with " + arguments.length + " argument(s)");
                args = Array.prototype.slice.call(arguments, 0);
                Function.prototype.apply.call(oldCallback, console, arguments);
            };
        };

        for (i = 0, j = methods.length; i < j; i++) {
            cur = methods[i];
            if (cur in console) {
                old = console[cur];
                console[cur] = generateNewMethod(old, cur);
            }
        }
    }

    window.onerror = function (msg, url, line) {
        alert("Window error: " + msg + ", " + url + ", line " + line);
    };
}());

console.log("ahh", "fdsa");
console.warn("f");

(function () {
    throw new Error("asdf");
}());

演示:http: //jsfiddle.net/HfPJ8/

于 2013-06-18T21:45:53.280 回答
0

您可以编写自己的日志框架或使用可用的日志框架,例如log4javascript,但我认为它们中的任何一个都不能从控制台重定向输出,您必须使用它try..catch来捕获错误或全局错误侦听器(这在浏览器中不是很可靠),然后通过框架的方法记录它们。

于 2013-06-18T21:41:15.223 回答
0

将代码放在 body 标记的顶部,或 html 页面中的任何位置。

<ul id="console-container"></ul>
<script>
(function(){
    let printOnScreen = function (...args) { // adds <li> on "console-container"
        let node = document.createElement("LI");             
        let textnode = document.createTextNode("console: " + args.join(" - ") );         
        node.appendChild(textnode);                              
        window.document.getElementById("console-container").appendChild(node);    
    };
    let methods = Object.keys(console) //get all console methods
    for (i = 0, j = methods.length; i < j; i++) {
        console[methods[i]] = printOnScreen; //override all methods
    }
    window.onerror = function (...args) { // catch all unhandled exceptions
        printOnScreen(args) 
    }
})();
</script>

于 2020-02-07T17:06:50.460 回答