php - 从输入中按位置从字符串中删除单词

Question

例子：

输入 = 2

文字 = aa bb cc

将变为：aa cc

位置的输入是 $_POST['position']

我有

$words = explode(" ", $_POST['string']);
for ($i=0; $i<count($words); $i++){ 
    echo $words[$i] . " ";
}

Answer 1

$to_remove = 2;
$text = "aa bb cc";

$words = explode(' ', $text);
if(isset($words[$to_remove -1])) unset($words[$to_remove -1]);
$text = implode(' ', $words);

Answer 2

$input = 2;
$words = explode(" ", $_POST['string']);
unset($words[$input-1]);
$words = implode(" ", $words);
echo $words;

Answer 3

这听起来像是一个家庭作业问题。不过，我会尝试一下：

代码：

<?php
    $string = trim($_POST['string']);
    $parts = explode(" ", string);
    $newString = "";
    $position = intval($_POST['position']);
    for($a = 0; $a < count($parts); $a++) {
        if($a != $position) { // or $a != ($position - 1) depending on if you passed in zero based position
            $newString = $newString . $parts[$a] . " ";
        }
    }
    $newString = trim($newString);

    echo "Old String: " . $string . "<br />";
    echo "New String: " . $newString;
?>

输出：

Old String: aa bb cc
New String: aa cc

Answer 4

拔出大枪REGEX !!!

$string = 'aa bb cc dd';
$input = 2;

$regex = $input - 1;
echo preg_replace('#^((?:\S+\s+){'.$regex.'})(\S+\s*)#', '$1', $string);

输出： aa cc dd

Answer 5

Foreach 循环往往使它更容易理解（IMO）。看起来也更干净。

$pos = 2;
$sentence = explode(" ", $_POST['string']);

foreach ($sentence as $index => $word) {
    if ($index != $pos - 1) {
        $result .= $word . ' ';
    }
}

echo $result;