1

我有一个 python 字典，我想将其转换为 json。

Python字典：

{"20090209.02s1.1_sequence.txt": [645045714, 3559.6422951221466, 206045184], "20090209.02s1.2_sequence.txt": [645045714, 3543.8322949409485, 234618880]}

期望的输出：

{
       "file_name":"20090209.02s1.1_sequence.txt",
       "file_information": [645045714, 3559.6422951221466, 206045184],

    {
       "file_name":"20090209.02s1.2_sequence.txt",
       "file_information": [645045714, 3543.8322949409485, 234618880],

    }
}

试过了，json.dumps但我没有得到想要的输出。

4

2 回答 2

16

您需要首先创建一个具有正确格式的结构：

import json

dict_ = {"20090209.02s1.1_sequence.txt": [645045714, 3559.6422951221466, 206045184], "20090209.02s1.2_sequence.txt": [645045714, 3543.8322949409485, 234618880]}
values = [{"file_name": k, "file_information": v} for k, v in dict_.items()]
json.dumps(values, indent=4)

请注意，所需的 JSON 输出对我来说似乎无效。这是此代码的输出：

[
    {
        "file_name": "20090209.02s1.1_sequence.txt", 
        "file_information": [
            645045714, 
            3559.6422951221466, 
            206045184
        ]
    }, 
    {
        "file_name": "20090209.02s1.2_sequence.txt", 
        "file_information": [
            645045714, 
            3543.8322949409485, 
            234618880
        ]
    }
]
于 2013-06-18T11:13:13.730 回答
1

将您的键值对拆分为单独的字典：

json.dumps([{'file_name': key, 'file_information': value} for key, value in yourdict.iteritems()])

请注意，您的输出顺序是任意的（字典没有固定的顺序）。您可能希望对输出进行排序以生成可预测的列表：

from operator import itemgetter

data = [{'file_name': key, 'file_information': value} for key, value in yourdict.iteritems()]
data.sort(key=itemgetter('file_name'))
json.dumps(data)

这会产生：

>>> data = [{'file_name': key, 'file_information': value} for key, value in yourdict.iteritems()]
>>> data.sort(key=itemgetter('file_name'))
>>> json.dumps(data)
'[{"file_name": "20090209.02s1.1_sequence.txt", "file_information": [645045714, 3559.6422951221466, 206045184]}, {"file_name": "20090209.02s1.2_sequence.txt", "file_information": [645045714, 3543.8322949409485, 234618880]}]'
>>> print json.dumps(data, indent=4)

[
    {
        "file_name": "20090209.02s1.1_sequence.txt",
        "file_information": [
            645045714,
            3559.6422951221466,
            206045184
        ]
    },
    {
        "file_name": "20090209.02s1.2_sequence.txt",
        "file_information": [
            645045714,
            3543.8322949409485,
            234618880
        ]
    }
]
于 2013-06-18T11:09:43.257 回答