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我正在使用这段代码对我的网站上的产品进行分页。现在的问题是所有产品一次加载。每页显示 36 个产品。

现在我需要做的是我需要产品一次加载 36 个，然后当我们点击下一步时，下一个 36 必须加载。有人可以帮忙吗？

    script type="text/javascript"> 
var jQuery12 = jQuery.noConflict();
jQuery12(document).ready(function(){
paginationhello();

});
function paginationhello(){

    //how much items per page to show
    var show_per_page = 36; 
    //getting the amount of elements inside content div
    var number_of_items = jQuery12('#content').children().size();
    //calculate the number of pages we are going to have
    var number_of_pages = Math.ceil(number_of_items/show_per_page);

    //set the value of our hidden input fields
    jQuery12('#current_page').val(0);
    jQuery12('#show_per_page').val(show_per_page);

    //now when we got all we need for the navigation let's make it '

    /* 
    what are we going to have in the navigation?
        - link to previous page
        - links to specific pages
        - link to next page
    */
    var navigation_html = '<a class="previous_link" href="javascript:previous();">Prev</a>';
    var current_link = 0;
    while(number_of_pages > current_link){
        navigation_html += '<a class="page_link" href="javascript:go_to_page(' + current_link +')" longdesc="' + current_link +'">'+ (current_link + 1) +'</a>';
        current_link++;
    }
    navigation_html += '<a class="next_link" href="javascript:next();">Next</a>';

    jQuery12('#page_navigation').html(navigation_html);

    //add active_page class to the first page link
    jQuery12('#page_navigation .page_link:first').addClass('active_page');

    //hide all the elements inside content div
    jQuery12('#content').children().css('display', 'none');

    //and show the first n (show_per_page) elements
   jQuery12('#content').children().slice(0, show_per_page).css('display', 'block');


}

function previous(){

    new_page = parseInt(jQuery12('#current_page').val()) - 1;
    //if there is an item before the current active link run the function
    if(jQuery12('.active_page').prev('.page_link').length==true){
        go_to_page(new_page);
    }

}

function next(){
    new_page = parseInt(jQuery12('#current_page').val()) + 1;
    //if there is an item after the current active link run the function
    if(jQuery12('.active_page').next('.page_link').length==true){
        go_to_page(new_page);
    }

}
function go_to_page(page_num){
    //get the number of items shown per page
    var show_per_page = parseInt(jQuery12('#show_per_page').val());

    //get the element number where to start the slice from
    start_from = page_num * show_per_page;

    //get the element number where to end the slice
    end_on = start_from + show_per_page;

    //hide all children elements of content div, get specific items and show them
    jQuery12('#content').children().css('display', 'none').slice(start_from, end_on).css('display', 'block');

    /*get the page link that has longdesc attribute of the current page and add active_page class to it
    and remove that class from previously active page link*/
    jQuery12('.page_link[longdesc=' + page_num +']').addClass('active_page').siblings('.active_page').removeClass('active_page');

    //update the current page input field
    jQuery12('#current_page').val(page_num);
}

</script>
4

1 回答 1

0

我可以告诉你，如何在 ajax 中做到这一点。确保将内容放入 content.xml 并将标记名从“sometag”更改为您想要的标记以放入表中。希望它会有所帮助。

<html>
<head>
<script type="text/javascript" >
var dataLoader;
var data;
var dataLength = 0;
var itemsPerPage = 10;
var noOfPages = 0;
var contentTable;

function createAjaxObject(){
var httpReq;
try {
    httpReq = new XMLHttpRequest();
} 
catch (e) {
    try {
        httpReq = new ActiveXObject("Msxml2.XMLHTTP");
    } 
    catch (e) {
        try {
            httpReq = new ActiveXObject("Microsoft.XMLHTTP");
        } 
        catch (e) {
            return false;
        }
    }
}
return httpReq;
}

function loadData(){
dataLoader = createAjaxObject();
dataLoader.onreadystatechange = onDataLoad;
dataLoader.open('GET', 'contents.xml', true);
dataLoader.send(null);
}

function onDataLoad(){
if (dataLoader.readyState != 4) 
    return;

if (dataLoader.status != 200 && dataLoader.status != 0) 
    return;

data = dataLoader.responseXML.documentElement.getElementsByTagName('content');
contentTable = document.getElementById('contents');
dataLength = data.length;
noOfPages = data.length / itemsPerPage;
displayPage(0);
buildNavMenu();
}

function displayPage(pagenum){

startItem = pagenum * itemsPerPage;
endItem = startItem + itemsPerPage;

while (contentTable.rows.length > 1) 
    contentTable.deleteRow(1);

for (i = startItem; i < endItem; i++) {
    newrow = contentTable.insertRow(-1);
    newrow.insertCell(-1).innerHTML = data[i].getElementsByTagName('sometag')[0].textContent;
    newrow.insertCell(-1).innerHTML = data[i].getElementsByTagName('sometag2')[0].textContent;
    newrow.insertCell(-1).innerHTML = data[i].getElementsByTagName('sometag3')[0].textContent;
}

}

function buildNavMenu(){
navMenu = document.getElementById('navMenu').rows[0];

for (i = 0; i < noOfPages; i++) {
    newcell = navMenu.insertCell(-1);
    newcell.innerHTML = i + 1;
    newcell.onclick = new Function("displayPage(" + i + ");");
}
}

</script>
</head>

<body onload="loadData()">
    <table width="500" border="1" id="contents">
        <tr>
            <th scope="col">Rank</th>

            <th scope="col">Name</th>

            <th scope="col">Earning</th>
        </tr>
    </table>

    <table id="navMenu" border="1">
        <tr>
            <td>
            </td>
        </tr>
    </table>
</body>
</html>

现在是 content.xml。

<?xml version="1.0" encoding="UTF-8"?>
<contents>
<content>

</content>
<content>

</content>
<content>

</content>
<content>

</content>
<content>

</content>
<content>

</content>
<content>

</content>
<content>

</content>
<content>

</content>
<content>

</content>
</content>

于 2013-06-18T09:22:09.657 回答