我想创建一个函数,该函数返回从所述字符串的开头到但不包括另一个特定字符串的开头的特定字符串的子字符串。想法?
所以像:
substrUpTo(theStr, subStr)
因此,如果我输入substrUpTo("Today is my birthday", "my")
,它将返回第一个参数的子字符串,但不包括第二个参数的开始位置。(即它会返回"Today is "
)
我想创建一个函数,该函数返回从所述字符串的开头到但不包括另一个特定字符串的开头的特定字符串的子字符串。想法?
所以像:
substrUpTo(theStr, subStr)
因此,如果我输入substrUpTo("Today is my birthday", "my")
,它将返回第一个参数的子字符串,但不包括第二个参数的开始位置。(即它会返回"Today is "
)
set s to "Today is my birthday"
set AppleScript's text item delimiters to "my"
text item 1 of s
--> "Today is "
内置offset
命令应该这样做:
set s to "Today is my birthday"
log text 1 thru ((offset of "my" in s) - 1) of s
--> "Today is "
可能有点笨拙,但它完成了工作......
property kSourceText : "Today is my birthday"
property kStopText : "my"
set newSubstring to SubstringUpToString(kSourceText, kStopText)
return newSubstring -- "Today is "
on SubstringUpToString(theString, subString) -- (theString as string, subString as string) as string
if theString does not contain subString then
return theString
end if
set theReturnString to ""
set stringCharacterCount to (get count of characters in theString)
set substringCharacterCount to (get count of characters in subString)
set lastCharacter to stringCharacterCount - substringCharacterCount
repeat with thisChar from 1 to lastCharacter
set startChar to thisChar
set endChar to (thisChar + substringCharacterCount) - 1
set currentSubstring to (get characters startChar thru endChar of theString) as string
if currentSubstring is subString then
return (get characters 1 thru (thisChar - 1) of theString) as string
end if
end repeat
return theString
end SubstringUpToString