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我有一个包含句子行的文件。我想打印所有超过 3 个单词的行。单词由空格分隔。
我怎么能这样做awk呢?
awk
像这样使用 awk:
awk 'NF>3' file
sed -E '/\s*(\S+\s+){3}\S+/!d' file
变量 NF 表示当前输入行的字段数。
I've an object that is include property ID with values between 101 and 199. How to order it like 199,101,102 ... 198?
199,101,102 ... 198
In result I want to put last item to f