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我设置了一个测试脚本，几乎与此处的示例完全相同： https ://github.com/GoodCloud/django-ajax-uploader

似乎开始上传文件（javascript 更新文件的名称和大小），但视图给我一个 500 错误与此消息。我找不到任何关于如何修复它的信息。

S3ResponseError: S3ResponseError: 400 Bad Request
<Error><Code>MalformedXML</Code><Message>The XML you provided was not well-formed or did not validate against our published schema</Message><RequestId>26E6EF8296A0E585</RequestId><HostId>F4QUOsVT4LxC+6OUP2lE1/9uPC77keOejyWs57GpS5kjvHXpun3U+81ntL8ZTgDa</HostId></Error>

我能够使用 boto 使用此处的命令在 shell 中上传文件： Upload 0 byte file to Amazon S3

风景：

from ajaxuploader.views import AjaxFileUploader
from ajaxuploader.backends.s3 import S3UploadBackend

import_uploader = AjaxFileUploader(backend=S3UploadBackend)

javascript:

var uploader = new qq.FileUploader({
    action: "/ajax/profile-upload/",
    element: $('#file-uploader')[0],
    multiple: true,
    onComplete: function(id, fileName, responseJSON) {
        if(responseJSON.success) {
            alert("success!");
        } else {
            alert("upload failed!");
        }
    },
    onAllComplete: function(uploads) {
        // uploads is an array of maps
        // the maps look like this: {file: FileObject, response: JSONServerResponse}
        alert("All complete!");
    },
    params: {
        'csrf_token': $('[name=csrfmiddlewaretoken]').val(),
        'csrf_name': 'csrfmiddlewaretoken',
        'csrf_xname': 'X-CSRFToken',
    },
});

模板：

<div id="file-uploader">       
    <noscript>          
        <p>Please enable JavaScript to use file uploader.</p>
    </noscript>         
</div>

我的 settings.py 文件中有 s3 访问变量（它们在 ajaxuploader/backends/s3.py 文件中调用）：

AWS_ACCESS_KEY_ID = myAccessKey
AWS_SECRET_ACCESS_KEY = mySecretKey
AWS_BUCKET_NAME = bucketName
4

1 回答 1

2

我使用自定义 s3 后端解决了这个问题，该后端覆盖了上传功能并使用 django-storages 而不是 boto 来保存文件。尝试这个 ：

from ajaxuploader.backends.base import AbstractUploadBackend
from django.core.files.storage import default_storage

class S3CustomUpload(AbstractUploadBackend):
    NUM_PARALLEL_PROCESSES = 4

    def upload_chunk(self, chunk):
        #save file to s3
        self._fd.write(chunk)
        self._fd.close()

    def setup(self, filename):
        self._fd = default_storage.open('%s/%s' % ('uploads/materials/', str(filename)), 'wb')

    def upload(self, uploaded, filename, raw_data, *args, **kwargs):
        try:
            if raw_data:
                # File was uploaded via ajax, and is streaming in.
                chunk = uploaded.read(self.BUFFER_SIZE)
                while len(chunk) > 0:
                    self.upload_chunk(chunk, *args, **kwargs)
                    chunk = uploaded.read(self.BUFFER_SIZE)
            else:
                # File was uploaded via a POST, and is here.
                for chunk in uploaded.chunks():
                    self.upload_chunk(chunk, *args, **kwargs)
            return True
        except:
            # things went badly.
            return False

    def upload_complete(self, request, filename, *args, **kwargs):
        upload = Upload()
        upload.upload = settings.S3_URL + "uploads/materials/"+ filename
        upload.name = filename
        upload.save()

        return {'pk': upload.pk}
于 2014-04-19T22:47:06.907 回答