我想用 C# 编写用于企业移动设备管理的 RESTful Web 服务，以发布下面由 Microsoft 定义的请求显示：
发布请求信息：
**Header:**
POST /EnrollmentServer/Discovery.svc HTTP/1.1
Content-Type: application/soap+xml; charset=utf-8
User-Agent: Windows Phone 8 Enrollment Client
Host: EnterpriseEnrollment.Contoso.com
Content-Length: xxx
Cache-Control: no-cache
<?xml version="1.0"?>
<s:Envelope xmlns:a="http://www.w3.org/2005/08/addressing"
xmlns:s="http://www.w3.org/2003/05/soap-envelope">
<s:Header>
<a:Action s:mustUnderstand="1">
http://schemas.microsoft.com/windows/management/2012/01/enrollment/IDiscoveryService/Discover
</a:Action>
<a:MessageID>urn:uuid: 748132ec-a575-4329-b01b-6171a9cf8478</a:MessageID>
<a:ReplyTo>
<a:Address>http://www.w3.org/2005/08/addressing/anonymous</a:Address>
</a:ReplyTo>
<a:To s:mustUnderstand="1">
https://ENROLLTEST.CONTOSO.COM/EnrollmentServer/Discovery.svc
</a:To>
</s:Header>
<s:Body>
<Discover xmlns="http://schemas.microsoft.com/windows/management/2012/01/enrollment/">
<request xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
<EmailAddress>user@contoso.com</EmailAddress>
<RequestVersion>1.0</RequestVersion>
</request>
</Discover>
</s:Body>
</s:Envelope>
发布回复信息
Header:
HTTP/1.1 200 OK
Content-Length: 865
Content-Type: application/soap+xml; charset=utf-8
Server: EnterpriseEnrollment.Contoso.com
Date: Tue, 02 Aug 2012 00:32:56 GMT
<s:Envelope xmlns:s="http://www.w3.org/2003/05/soap-envelope"
xmlns:a="http://www.w3.org/2005/08/addressing">
<s:Header>
<a:Action s:mustUnderstand="1">
http://schemas.microsoft.com/windows/management/2012/01/enrollment/IDiscoveryService/DiscoverResponse
</a:Action>
<ActivityId>
d9eb2fdd-e38a-46ee-bd93-aea9dc86a3b8
</ActivityId>
<a:RelatesTo>urn:uuid: 748132ec-a575-4329-b01b-6171a9cf8478</a:RelatesTo>
</s:Header>
<s:Body xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema">>
<DiscoverResponse
xmlns="http://schemas.microsoft.com/windows/management/2012/01/enrollment">
<DiscoverResult>
<AuthPolicy>OnPremise</AuthPolicy>
<AuthUrl/>
<EnrollmentPolicyServiceUrl>
https://enrolltest.contoso.com/ENROLLMENTSERVER/DEVICEENROLLMENTWEBSERVICE.SVC
</EnrollmentPolicyServiceUrl>
<EnrollmentServiceUrl>
https://enrolltest.contoso.com/ENROLLMENTSERVER/DEVICEENROLLMENTWEBSERVICE.SVC
</EnrollmentServiceUrl>
<FederatedServiceName/>
<FederatedServicePolicy/>
</DiscoverResult>
</DiscoverResponse>
</s:Body>
</s:Envelope>
我想知道我应该如何在我的网络服务中为 POST 调用创建 WebInvoke 方法？
使用下面的原型，我可以发送和接收soap xml，但不确定这种方法是否可以实现？
[OperationContract]
[WebInvoke(Method = "POST",
UriTemplate = "",
BodyStyle = WebMessageBodyStyle.Bare,
RequestFormat = WebMessageFormat.Xml,
ResponseFormat = WebMessageFormat.Xml)]
XmlElement Post(Stream xmlData);
我也尝试过使用下面定义的类对象，但是使用 WCF 测试客户端我可以看到生成的 soap xml，但是当尝试从测试应用程序访问这个 Web 服务时，我只得到类对象的 xml 内容和没有看到任何肥皂标题和正文元素。
[OperationContract]
[WebInvoke(Method = "POST",
UriTemplate = "",
BodyStyle = WebMessageBodyStyle.WrappedRequest,
RequestFormat = WebMessageFormat.Xml,
ResponseFormat = WebMessageFormat.Xml)]
DiscoverResponse Discover(Discover request);
其中 DiscoverResponse 是 POST 响应的 DataContract 类， Discover 是 POST 请求的 DataContract 类。
我需要对上述方法进行哪些更改才能获得整个soap xml而不是仅body xml的响应？
感谢您提前回答。