1

我目前正在做一些关于数据挖掘的研究，我的研究数据表如下

ID   Author  
1    Ali,Ahmad,David,Kumar
2    Aslam,Abid,John

现在我想用 position_ID 将逗号分隔的作者姓名拆分为多行，例如

ID         Author         Position_ID  
1          Ali                 1
1          Ahmad               2
1          David               3
1          Kumar               4
2          Aslam               1
2          Shahzad             2
2          John                3

我目前已经做了一个拆分函数和以下查询，它只能将作者列值拆分为多行，但不能将字符串中的作者 position_ID 获取到单独的列中。请给我一些建议！[在此处输入图片描述][1]提前致谢

CREATE Function [dbo].[SplitString]
(@List Varchar(Max), @Delimiter Char(1))
Returns @Items 
Table (Item Varchar(max))
As
Begin
Declare @Item Varchar(max), @Pos TinyInt
While Len(@List) > 0 
Begin
Set @Pos = CharIndex(@Delimiter, @List)
If @Pos = 0 Set @Pos = Len(@List) + 1 
Set @Item = Left(@List, @Pos - 1)
Insert @Items 
Select Ltrim(Rtrim(@Item))
Set @List = SubString(@List, @Pos + Len(@Delimiter), Len(@List))
End
Return
End

declare @TAB table (strg varchar(max),Research_ID bigint)
insert @TAB
select authors,Research_ID from Citation
Select S.item As [Authors],Research_ID
From @TAB T
Cross apply [dbo].[SplitString](T.strg,',') S;
4

1 回答 1

1

请试试这个

CREATE function [dbo].[listtorow2](@l varchar(200),@id int) 返回 @csv table(strdata varchar(20),id INT,Position_ID int) 作为开始

  declare @xml xml
  set @xml = '<root><record>' + replace(@l,',','</record><record>') +
 '</record></root>'

  insert into @csv(strdata,id,Position_ID)

select *,@id,ROW_NUMBER()OVER(ORDER BY (SELECT 1)) from(
select  t.value('.','varchar(150)') as [items]
from @xml.nodes('//root/record') as a(t)) data

  return
end

go

DECLARE @t TABLE(id INT,autor VARCHAR(50))
INSERT INTO @t(id,autor)values (1,'Ali,Ahmad,David,Kumar'),(2,'Aslam,Abid,John')


SELECT t.id,strdata,Position_ID
FROM @t t 
CROSS APPLY[dbo].[listtorow2](t.autor,id) t1
于 2013-08-21T15:11:38.547 回答