0

如何使用 RestTemplate 发布到 REST 服务。我有以下 RESTful Web 服务,我想使用 RestTemplate 将新用户对象发布到?

@Controller
@RequestMapping("/api")
class APIController
{

    private static final Logger logger = LoggerFactory.getLogger(APIController.class);

    private MappingJacksonJsonView  jsonView = new MappingJacksonJsonView();

    @RequestMapping(value = "/{id}", method = RequestMethod.POST)
    @ResponseBody
    public User updateCustomer(@PathVariable("id") String id, @RequestBody User user) {

        logger.debug("I am in the controller and got user name: " + user.toString());
        return user;
    }
}

如何更改以下代码以发布用户对象?

    RestTemplate rt = new RestTemplate(commons);
    rt.getMessageConverters().add(new MappingJacksonHttpMessageConverter());
    rt.getMessageConverters().add(new StringHttpMessageConverter());

    URI uri = new URI("http://" + mRESTServer.getHost() + ":8080/springmvc-rest-secured-test/api/2");

    User u = new User();
    u.setName("Johnathan M Smith");
    u.setUser("JMS");


    User returns = rt.postForObject(uri, u, User.class);

    LOGGER.debug("User:  " + u.toString());

这是我得到的错误和输出:

    2013-06-18 08:11:36,819 [main] ERROR com.johnathanmarksmith.springresttemplate.Main - error:  <html><head><title>JBoss Web/7.0.13.Final - Error report</title><style><!--H1 {font-family:Tahoma,Arial,sans-serif;color:white;background-color:#525D76;font-size:22px;} H2 {font-family:Tahoma,Arial,sans-serif;color:white;background-color:#525D76;font-size:16px;} H3 {font-family:Tahoma,Arial,sans-serif;color:white;background-color:#525D76;font-size:14px;} BODY {font-family:Tahoma,Arial,sans-serif;color:black;background-color:white;} B {font-family:Tahoma,Arial,sans-serif;color:white;background-color:#525D76;} P {font-family:Tahoma,Arial,sans-serif;background:white;color:black;font-size:12px;}A {color : black;}A.name {color : black;}HR {color : #525D76;}--></style> </head><body><h1>HTTP Status 400 - </h1><HR size="1" noshade="noshade"><p><b>type</b> Status report</p><p><b>message</b> <u></u></p><p><b>description</b> <u>The request sent by the client was syntactically incorrect ().</u></p><HR size="1" noshade="noshade"><h3>JBoss Web/7.0.13.Final</h3></body></html>
Exception in thread "main" org.codehaus.jackson.JsonParseException: Unexpected character ('<' (code 60)): expected a valid value (number, String, array, object, 'true', 'false' or 'null')
 at [Source: java.io.StringReader@71290aac; line: 1, column: 2]
4

2 回答 2

1

我明白了.. 为 RESTful 服务编写用户对象的程序员没有

public User()
{
}

一旦将其添加到用户对象中,一切正常..这不是客户端问题..它在服务器端

于 2013-06-18T12:44:11.650 回答
0

我注意到至少两个问题:

第一个是您将请求发送到错误的 url。我们的控制器方法的请求映射如下:

@RequestMapping(value = "/user/{id}", method = RequestMethod.POST )

但是您将请求发送到 url:

"http://" + mRESTServer.getHost() + ":8080/springmvc-rest-secured-test/json/user/2"

您可能希望从路径中删除字符串“json”。

第二个问题是您的控制器方法返回一个User对象,但是当您调用该类的postForObject()方法时RestTemplate,您声明控制器方法的返回类型是String.

你应该改变这一行:

String returns = rt.postForObject(uri, u, String.class);

至:

User returns = rt.postForObject(uri, u, User.class);

有关此内容的更多详细信息,请参阅 RestTemplate 类的 Javadoc

于 2013-06-17T20:44:14.400 回答