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您好，我有一个 Symfony2 控制器从两个不同的客户端接收 POST。一个 Web 应用程序，它使用 $.post (JQuery) 和一个使用 NSURLRequest 的 Objective C iPhone APP 发送数据。在这两种情况下，我都会生成一个 JSON 字符串并通过 POST 发送它。

为什么我会根据客户端获得不同的请求内容？检查以下内容：

jQuery 方法

$.post(myURL, {hist_id: 15}, function(json){}, "json");

获取此请求对象：

POST /~pgbonino/Symfony/web/app.php/api/saveTest HTTP/1.1
Accept:               application/json, text/javascript, */*; q=0.01
Accept-Encoding:      gzip, deflate
Accept-Language:      es-es
Connection:           keep-alive
Content-Length:       17053
Content-Type:         application/x-www-form-urlencoded; charset=UTF-8
Cookie:               PHPSESSID=9l9tkkcm1via94rclfshbajvj5
Host:                 127.0.0.1
Origin:               http://127.0.0.1
Referer:              http://127.0.0.1/~pgbonino/Symfony/web/app.php/dotest/9?t=5400&c=1&w=33&m=e&o=h&save_configuration=false
Surrogate-Capability: symfony2="ESI/1.0"
User-Agent:           Mozilla/5.0 (Macintosh; Intel Mac OS X 10_8_4) AppleWebKit/536.30.1 (KHTML, like Gecko) Version/6.0.5 Safari/536.30.1
X-Php-Ob-Level:       1
X-Requested-With:     XMLHttpRequest

hist_id=15 [] [] // <-- Take a look at the content of the Request. Here I get an URL style string!!

在这种情况下，当我在 Symfony 控制器中进行操作时，$this->getRequest()->get('hist_id')我得到了完美的 15。

目标 C 方法

NSDictionary *myDict = [NSDictionary dictionaryWithObjectsAndKeys: [NSString stringWithFormat: @"%d", 15], @"hist_id"];
NSData* requestData = [NSJSONSerialization myDict options:nil error:&error];
NSLog(@"JSON string:%@", [[NSString alloc] initWithData:requestData encoding:NSUTF8StringEncoding]); // To check that the conversion to JSON is indeed being performed perfectly!!

[request setValue:@"application/json" forHTTPHeaderField:@"Accept"];
[request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[request setValue:@"XMLHttpRequest" forHTTPHeaderField:@"X-Requested-With"];

[request setValue:[NSString stringWithFormat:@"%d", [requestData length]] forHTTPHeaderField:@"Content-Length"];
[request setHTTPBody: requestData];

获取此请求对象：

POST /~pgbonino/Symfony/web/app.php/api/saveTest HTTP/1.1
Accept:               application/json
Accept-Encoding:      gzip, deflate
Accept-Language:      en-us
Connection:           keep-alive
Content-Length:       15
Content-Type:         application/json
Cookie:               PHPSESSID=5l272k3858k96s3giajugslv76
Host:                 127.0.0.1
Surrogate-Capability: symfony2="ESI/1.0"
User-Agent:           PreparaTest/1.0 CFNetwork/609.1.4 Darwin/12.4.0
X-Php-Ob-Level:       1

{"hist_id":"0"} [] [] // <-- Take a look at the content of the Request. Here I get a JSON plain text!!

在这种情况下，当我在 Symfony 控制器中执行操作时，$this->getRequest()->get('hist_id')我得到了 null。

为什么会有这样的区别？为什么请求的内容在一种情况下是 Request 和 Symfony2 控制器可读的 URL 字符串，而在第二种情况下 JSON 没有被转换并且我无法读取其中的变量？

json_decode或者这是正常的方式，我必须检查“谁”在叫我做$request->getContent();什么？

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2 回答 2

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If you want your iPhone send data that can be parsed with $this->getRequest()->get('hist_id') you need to encode your data not in JSON but in x-www-form-urlencoded. To do so you need convert your Dictionary to String and then encode it to be correct url-encoded string. You can find info about this here: https://developer.apple.com/library/ios/#documentation/NetworkingInternetWeb/Conceptual/NetworkingOverview/WorkingWithHTTPAndHTTPSRequests/WorkingWithHTTPAndHTTPSRequests.html

To convert dict to string you can use code from Turning a NSDictionary into a string using blocks?

NSMutableArray* parametersArray = [[[NSMutableArray alloc] init] autorelease];
[dict enumerateKeysAndObjectsUsingBlock:^(id key, id obj, BOOL *stop) {
    [parametersArray addObject:[NSString stringWithFormat:@"%@=%@", key, obj]];
}];
NSString* parameterString = [parametersArray componentsJoinedByString:@"&"];
于 2013-06-18T05:09:32.217 回答
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查看 jquery.post() 的文档（http://api.jquery.com/jQuery.post/）：

jQuery.post( url [, data ] [, success(data, textStatus, jqXHR) ] [, dataType ] )


dataType
Type: String
The type of data expected from the server. 
Default: Intelligent Guess (xml, json, script, text, html).

第四个变量是来自服务器的预期数据类型。所以你的第二个变量 ({hist_id: 15}) 没有被转换为 json。这就是为什么它被作为一个普通的 post 变量发送。

于 2013-06-17T23:37:22.403 回答