在 Python 中,如果我打开一个不存在的二进制文件,程序会以错误退出并打印:
Traceback (most recent call last):
File "C:\Python_tests\Exception_Handling\src\exception_handling.py",
line 4, in <module>
pkl_file = open('monitor.dat', 'rb')
IOError: [Errno 2] No such file or directory: 'monitor.dat'
我可以用“try-except”来处理这个问题,比如:
try:
pkl_file = open('monitor.dat', 'rb')
monitoring_pickle = pickle.load(pkl_file)
pkl_file.close()
except Exception:
print 'No such file or directory'
我怎么能在捕获的异常中打印以下行?
File "C:\Python_tests\Exception_Handling\src\exception_handling.py",
line 11, in <module>
pkl_file = open('monitor.dat', 'rb')
所以程序不会退出。