这是我所追求的 MWE,改编自这个问题:
from matplotlib.pyplot import plot, draw, show
def make_plot():
plot([1,2,3])
draw()
print 'continue computation'
print('Do something before plotting.')
# Now display plot in a window
make_plot()
answer = raw_input('Back to main and window visible? ')
if answer == 'y':
print('Excellent')
else:
print('Nope')
show()
我想要的是:我调用函数来制作绘图,出现绘图窗口,然后我回到提示符,以便我可以输入一些值(基于刚刚显示的图像)并继续使用代码(然后窗口可以关闭或保留在那里,我不在乎)。
相反,我得到的是带有绘图的窗口仅在代码完成后出现,这不好。
添加 1
我已经尝试了以下相同的结果,绘图窗口出现在代码的末尾而不是之前:
from matplotlib.pyplot import plot, ion, draw
ion() # enables interactive mode
plot([1,2,3]) # result shows immediately (implicit draw())
# at the end call show to ensure window won't close.
draw()
answer = raw_input('Back to main and window visible? ')
if answer == 'y':
print('Excellent')
else:
print('Nope')
如果我更改draw()
为show()
.
添加 2
我尝试了以下方法:
from multiprocessing import Process
from matplotlib.pyplot import plot, show
def plot_graph(*args):
for data in args:
plot(data)
show()
p = Process(target=plot_graph, args=([1, 2, 3],))
p.start()
print 'computation continues...'
print 'Now lets wait for the graph be closed to continue...:'
p.join()
这会导致消息Python kernel has crashed
出错Canopy
:
The kernel (user Python environment) has terminated with error code -6. This may be due to a bug in your code or in the kernel itself.
Output captured from the kernel process is shown below.
[IPKernelApp] To connect another client to this kernel, use:
[IPKernelApp] --existing /tmp/tmp9cshhw.json
QGtkStyle could not resolve GTK. Make sure you have installed the proper libraries.
[xcb] Unknown sequence number while processing queue
[xcb] Most likely this is a multi-threaded client and XInitThreads has not been called
[xcb] Aborting, sorry about that.
python: ../../src/xcb_io.c:274: poll_for_event: La declaración `!xcb_xlib_threads_sequence_lost' no se cumple.
我应该提到我正在运行Canopy
的elementary OS
基于Ubuntu 12.04
.
添加 3
还尝试了此问题中发布的解决方案:
import numpy
from matplotlib import pyplot as plt
if __name__ == '__main__':
x = [1, 2, 3]
plt.ion() # turn on interactive mode
for loop in range(0,3):
y = numpy.dot(x, loop)
plt.figure()
plt.plot(x,y)
plt.show()
_ = raw_input("Press [enter] to continue.")
随着代码的推进(即:用户点击 [enter]),这将显示空的绘图窗口,并且仅在代码完成后显示图像。
此解决方案(也在同一个问题中)甚至不显示绘图窗口:
import numpy
from matplotlib import pyplot as plt
if __name__ == '__main__':
x = [1, 2, 3]
plt.ion() # turn on interactive mode, non-blocking `show`
for loop in range(0,3):
y = numpy.dot(x, loop)
plt.figure() # create a new figure
plt.plot(x,y) # plot the figure
plt.show() # show the figure, non-blocking
_ = raw_input("Press [enter] to continue.") # wait for input from the user
plt.close() # close the figure to show the next one.