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我无法让 BigInteger 向其中添加另一个 BigInteger。任何建议相关代码:

在课堂上声明:

private BigInteger mTotientSum; 

在构造函数中完成:

BigInteger mTotientSum = BigInteger.ZERO;

在相对方法中:

  BigInteger totientMultiplier = BigInteger.valueOf(mTotientMulitplier);
  for (long i = 1; i <= mMaxNum; i++)
  {
     BigInteger j = BigInteger.valueOf(i);
     System.out.println(j.toString());
     BigInteger num = j.multiply(totientMultiplier);
     System.out.println(num.toString());
     BigInteger totient = calculateTotient(num);
     System.out.println(totient);
     mTotientSum = mTotientSum.add(totient); //This is line 113
     System.out.println("Sum at" + i + " = " + mTotientSum.toString());
  }

我得到的输出是:

1
510510
17
16
16
Exception in thread "main" java.lang.NullPointerException
          at Totient.run(Totient.java:113) (Note that line 113 is noted above.)
      at Totient.main(Totient.java:131)
4

1 回答 1

2

您在构造函数中隐藏变量。通过调用

BigInteger mTotientSum = BigInteger.ZERO;

您只是在初始化一个本地 mTotientSum 变量并将类字段留空。

不要在构造函数中重新声明变量。而是这样做:

mTotientSum = BigInteger.ZERO;

看到不同?

于 2013-06-16T23:15:32.097 回答