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我可以在mysql中获得多个条件的错误总数吗？

我的要求是，我需要获得具有某些优先级的 bugid 的总和或计数，比如 P1，它超过了特定时间，但是超出的计数应该从该特定优先级的总计数中计算出来。

我的查询是：-

select 
sum(
 IF(priority="P1",1,0)) P1, 
sum(
 IF(timediff(delta_ts,creation_ts) > "00:00:05",1,0))P1_exeeded,
SUM(
 IF(priority="P2",1,0)) P2,
sum(
 IF(timediff(delta_ts,creation_ts) > "00:00:10",1,0))P2_exeeded,
SUM(
 IF(priority="P3",1,0)) P3count,
SUM(
 IF(priority="P4",1,0)) P4count,
SUM(
 IF(priority="P5",1,0)) P5count,
SUM(
 IF(priority="P6",1,0)) P6count,
SUM(
 IF(priority="P7",1,0)) P7count,
SUM(
 IF(priority="P8",1,0)) P8count 
from bugs 
where bugs.product_id=237 
and bugs.resolution='FIXED' 
and bugs.creation_ts >='2013-06-14 09:00:00' 
and bugs.creation_ts <= '2013-06-16 08:59:59' 
and bug_status="RESOLVED";

我得到的结果是： -

------+------------+------+------------+---------+ ---------+---------+---------+---------+---------+
| P1 | P1_exeeded | P2 | P2_exeeded | P3count | P4count | P5count | P6count | P7count | P8count |
+--------+------------+------+------------+--------- +---------+---------+---------+---------+--------- +
| 7 | 19 | 6 | 18 | 5 | 1 | 0 | 0 | 0 | 0 |
+--------+------------+------+------------+--------- +---------+---------+---------+---------+--------- +
一组中的 1 行（0.00 秒）

但是我需要通过以下两个条件来计算每个优先级中超出的错误 ID 的总和：-

超过特定时间限制的超出 bugid 的总和，其取自其特定优先级类别的计数。

在每种情况下，超出的错误 ID 总和应满足这两个条件。

我拥有的 P1 优先级错误 ID 总数。P1_exeeded = IF(timediff(delta_ts,creation_ts) > "00:00:05",1,0)) 取自 P1 bugid 的计数。

请帮助在mysql中使用sum（满足2个条件）

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2 回答 2

2

我得到了答案。谢谢 Chetan.:-

select 
sum(
 IF(priority="P1",1,0)) P1,
sum( 
 IF((timediff(delta_ts,creation_ts) > "00:02:00") && (priority="P1") ,1,0))P1_exeeded,
SUM(
 IF(priority="P2",1,0)) P2,sum( IF((timediff(delta_ts,creation_ts) > "00:01:00") && (priority="P2") ,1,0))P2_exeeded,
SUM(
 IF(priority="P3",1,0)) P3count,
SUM(
 IF(priority="P4",1,0)) P4count,
SUM(
 IF(priority="P5",1,0)) P5count,
SUM(
 IF(priority="P6",1,0)) P6count,
SUM(
 IF(priority="P7",1,0)) P7count,
SUM(
  IF(priority="P8",1,0)) P8count 
from bugs ....
where
.....

+--------+------------+------+------------+--------- +---------+---------+---------+---------+--------- +
| P1 | P1_exeeded | P2 | P2_exeeded | P3count | P4count | P5count | P6count | P7count | P8count |
+--------+------------+------+------------+--------- +---------+---------+---------+---------+--------- +
| 7 | 1 | 6 | 1 | 5 | 1 | 0 | 0 | 0 | 0 |
+--------+------------+------+------------+--------- +---------+---------+---------+---------+--------- +
于 2013-06-16T05:26:20.707 回答
0 
SELECT `customer xxx`,
cxType,
`Order Store`,
sum(if(category='xxxx',qty,0)), 
min(`order date`) as 'First Purchcase Date'
FROM table1
group by `customer xxx`;
于 2017-07-18T18:36:40.387 回答