1

我不确定标题,任何人都可以随意编辑

桌子articles

+----------+-------------------------+----------+
|   id     |  title                  | status   |
+----------+-------------------------+----------+
|    1     |  title 1                | accepted |
+----------+-------------------------+----------+
|    2     |  title 2                | accepted |
+----------+-------------------------+----------+
|    3     |  title 3                | rejected |
+----------+-------------------------+----------+
|    4     |  title 4                | accepted |
+----------+---------+---------------+----------+

桌子article_reviewers

+----------+------------+-----------+
|   id     | article_id |  user_id  |
+----------+------------+-----------+
|    1     |     1      |     1     |
+----------+------------+-----------+
|    2     |     2      |     1     |
+----------+------------+-----------+
|    3     |     3      |     1     |
+----------+------------+-----------+
|    4     |     2      |     2     |
+----------+------------+-----------+

我如何从该表中找到每个用户和每个状态的文章总数。

从表中:
用户id 1有 2 篇被接受的文章和 1 篇被拒绝的文章。
拥有的用户id 2,有 1 篇被接受的文章和 0 篇被拒绝的文章。

如果我做类似的事情:

SELECT count(*) total FROM article_reviewers ar
INNER JOIN articles a
ON ar.article_id = a.id
GROUP BY ar.user_id

我得到了每个用户的总文章,我怎样才能找到每个状态?
有人可以告诉我如何做到这一点,我很无能为力。

4

1 回答 1

2

你快到了:

SELECT ar.user_id, a.status, count(*) total
FROM article_reviewers ar
INNER JOIN articles a
ON ar.article_id = a.id
GROUP BY ar.user_id, a.status
于 2013-06-15T12:01:16.623 回答