此代码没有给我任何错误或警告,但无法正常工作,我不知道问题出在哪里,请帮助我。
package com.example.webtest; import org.ksoap2.SoapEnvelope; import android.util.Log; import org.ksoap2.serialization.SoapObject; import org.ksoap2.serialization.SoapPrimitive; import org.ksoap2.serialization.SoapSerializationEnvelope; import org.ksoap2.transport.HttpTransportSE; import android.os.Bundle; import android.app.Activity; import android.view.Menu; import android.view.View; import android.widget.Button; import android.widget.EditText; import android.widget.TextView; public class MainActivity extends Activity { String UserFahrenheit; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); Button b=(Button) findViewById(R.id.button); final EditText Med=(EditText) findViewById(R.id.MedServTextView); final TextView Test=(TextView) findViewById(R.id.TestTextView); b.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { //try{ UserFahrenheit=Med.getText().toString(); //String mobile=getData(UserMRN.trim()); String NAMESPACE = "http://tempuri.org/"; String METHOD_NAME = "FahrenheitToCelsius"; String SOAP_ACTION = "http://tempuri.org/FahrenheitToCelsius"; String URL = "http://www.w3schools.com/webservices/tempconvert.asmx?WSDL"; SoapObject Request = new SoapObject(NAMESPACE, METHOD_NAME); Request.addProperty("Fahrenheit",UserFahrenheit.trim()); SoapSerializationEnvelope envelope = new SoapSerializationEnvelope( SoapEnvelope.VER11); envelope.dotNet = true; envelope.setOutputSoapObject(Request); HttpTransportSE androidHttpTransport = new HttpTransportSE( URL); try{ androidHttpTransport.call(SOAP_ACTION, envelope); SoapPrimitive response = (SoapPrimitive) envelope.getResponse(); String Celsius; Celsius= String.valueOf(response.toString()); Test.setText(Celsius); }catch(Exception e){ e.getMessage(); } // }catch(Exception e){ // e.getMessage(); // } } }); } @Override public boolean onCreateOptionsMenu(Menu menu) { // Inflate the menu; this adds items to the action bar if it is present. getMenuInflater().inflate(R.menu.main, menu); return true; } }
问问题
14710 次
1 回答
1
你为什么使用 SoapPrimitive?首先,检查您的响应是否为错误。否则,通过调用 response.bodyIn 从响应对象中获取响应体:
SoapObject response = null;
if (envelope.bodyIn instanceof SoapObject) { // SoapObject = SUCCESS
response = (SoapObject) envelope.bodyIn;
} else if (envelope.bodyIn instanceof SoapFault) { // SoapFault =
// FAILURE
SoapFault soapFault = (SoapFault) envelope.bodyIn;
throw new Exception(soapFault.getMessage());
}
然后,您可以通过调用 response.getProperty("responsecode") 从响应中获取属性。
此外,在调试时将 HttpTransportSE 的调试值设置为 true:
transportSE.debug = true;
于 2013-06-15T11:34:36.843 回答