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我正在尝试制作一个包含用于文件选择的easygui的单词计数器程序。我目前使用带有 PyDev 插件的 Eclipse SDK（如果有更好的 Python 环境的建议）。

这是我当前状态的代码：

#This program is supposed to take a word file, and count the amount of lines and
#words. If the entered file is not a .txt, .doc, or .docx, then the program will
#ask for a different file.

from easygui import fileopenbox

filename = fileopenbox()
lines, words = 0, 0

#This method will count the amount of lines and words in a program and display
#it to the user
def word_count():
    if filename.endswith('.docx'): #If the file extension is .docx
        print("Your file has" + num_words + "words") #Print the amount of lines and words in the file.
    elif filename.endswith('.doc'): #If the file extension is .doc
        #<CODE WHICH COUNTS LINES AND WORDS>
        print("Your file has", lines, "lines, and" ,"words") #Print the amount of lines and words in the file.
    elif filename.endswith('.txt'): #If the file extension is .txt
        #<CODE WHICH COUNTS LINES AND WORDS>
        print("Your file has", lines, "lines, and" ,"words") #Print the amount of lines and words in the file.
    elif filename.endswith('.py'): #If the file extension is .py
        #<CODE WHICH COUNTS LINES AND WORDS>
        print("Your file has", lines, "lines, and" ,"words") #Print the amount of lines and words in the file.
    elif filename.endswith('.java'): #If the file extension is .java
        #<CODE WHICH COUNTS LINES AND WORDS>
        print("Your file has", lines, "lines, and" ,"words") #Print the amount of lines and words in the file.
    else:
        print("Are you trying to annoy me? How about giving me a TEXT or SOURCE CODE file, genius?")#Print an insulting error message.

如代码所示，我希望程序读取文件扩展名，如果它与其中任何一个匹配，则运行字数统计代码。但是，我的问题是，字数统计代码是什么？似乎使用 easygui 中的 fileopenbox() 会使事情变得更加复杂。提前感谢任何帮助

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1 回答 1

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from easygui import fileopenbox

def word_count(filename):
    if not filename.endswith(('.txt', '.py', '.java')):
        print('Are you trying to annoy me? How about giving me a TEXT or SOURCE CODE file, genius?')
        return

    with open(filename) as f:
        n_lines = 0
        n_words = 0
        for line in f:
            n_lines += 1
            n_words += len(line.split())
    print('Your file has {} lines, and {} words'.format(n_lines, n_words))

filename = fileopenbox()
word_count(filename)
于 2013-06-15T05:26:26.650 回答