linux - Prevent bash script from hanging

Question

Suppose I have bash-script with following code:

function test() {
  some_code
  ...
  make
  some_code
}

test
some_other_code

test() could contain any code that might run unreasonably long.

I was trying to use something like:

function test() {
  cd $WORK_FOLDER
  make
}

run_timeout()
{
local timeout=$1
$2 &
local pid=$!
while ps $pid >/dev/null && [ $timeout -ne 0 ]; do
  sleep 1
  let timeout--  
done  
kill -9 $pid 2>/dev/null && echo "Process $pid killed because executed too long"
}

run_timeout 15 "test"
run_timeout 5 "test"

But make was still running after the estimated time.

Any suggestion how to solve this problem?

Is there any technique that prevents a bash script from hanging?

Answer 1

我猜 $2 & 是你运行 long 函数的地方吗？我有同样的问题，有一段时间，根据函数中的内容，你将有多个进程......我不知道我的解决方案是否是最好的方法，但它对我有用。

改变 ：

$2 &

为了 ：

awk '{system($2)}' &

这样，pid =$！会给你 awk pid，通过杀死 awk，你会杀死整个过程。