1

我目前正在开发一个非常简单的 ListView，最多有 2 种不同的视图类型。为了使一切顺利，我尝试回收视图。我的代码现在是：

@Override
public int getItemViewType (int position){
    if(mHasBefore&&position==0){
        return TYPE_PAGER;
    }else if(mHasNext&&position==getCount()-1){
        return TYPE_PAGER;
    }else return TYPE_SCORE;
}
@Override
public int getViewTypeCount (){
    return 1+((mHasBefore==true||mHasNext==true)?1:0);
}@Override
public View getView(int position, View convertView, ViewGroup parent) {
    Log.d("outa","View: pos: "+position+ " . "+getItemViewType(position)+" - "+getViewTypeCount());
    if(getItemViewType(position)==TYPE_SCORE)return getScoreView(position,convertView,parent);
    else return getPagerView(position,convertView,parent);
}
protected View getPagerView(int position,View convertView,ViewGroup parent){
    if (convertView == null){
        convertView = LayoutInflater.from(parent.getContext()).inflate(
                R.layout.listitem_highscore_pager, null);}}
protected View getScoreView(int position,View convertView,ViewGroup parent){
    if (convertView == null){
        convertView = LayoutInflater.from(parent.getContext()).inflate(
                R.layout.listitem_highscore, null);}}

基本上它应该在最后一项上显示不同的视图，但即使 LogCat 在 getView() 中声明它不是 TYPE_SCORE，它仍然显示默认项。因此 convertView 确实提供了一个回收的视图。我做错了什么还是这是正常行为？

4

3 回答 3

5

干得好：

    private static final int TYPE_PAGER = 0;
    private static final int TYPE_PAGER = 1;
    private static final int VIEW_COUNT = 2;

    private LayoutInflater mInflater = LayoutInflater.from(context);

    @Override
    public int getViewTypeCount (){
            return VIEW_COUNT;
    }

    @Override
    public View getView(int position, View convertView, ViewGroup parent) {
                ViewHolder holder;
                ViewHolder2 holder2;
                int type = getItemViewType(position);

                if (convertView == null) {
                    holder = new ViewHolder();
                    holder2 = new ViewHolder2();
                    switch(type){
                    case TYPE_SCORE:
                        Log.i(TAG, "ConvertView type1");
                        convertView = mInflater.inflate(R.layout.listitem_highscore, null);
                        convertView.setTag(R.layout.listitem_highscore, holder);
                    break;
                    case TYPE_PAGER:
                        Log.i(TAG, "ConvertView type0");
                        convertView = mInflater.inflate(R.layout.listitem_highscore_pager, null);
                        convertView.setTag(R.layout.listitem_highscore_pager, holder2);
                    break;

                    }
}

                } else{
                    // Get the ViewHolder back to get fast access to the TextViews
                    holder = (ViewHolder) convertView.getTag(R.layout.baseadapter);
                    holder2 = (ViewHolder2)convertView.getTag(R.layout.baseadapter1);
                }


                switch(type){
            case TYPE_SCORE:
               holder.holderText.setText("type1");
            break;
            case TYPE_PAGER:
               holder2.holder2Text.setText("type2");
            break;

            }
    }

观点持有者：

 static class ViewHolder {
      //Place your views here for example:
      TextView holderText;

  }

 static class ViewHolder2{
       TextView holder2Text;
  }
于 2013-06-14T12:13:36.260 回答
1

getItemViewType()必须返回稳定值。IOW，对于positionof 0，getItemViewType()必须始终返回TYPE_PAGER，而不是基于其他mHasBefore值。

如果您希望获得不稳定的值，则notifyDataSetChanged()每次需要更改值时都需要调用。IOW，如果您mHasBefore从原来的任何位置切换，则需要调用notifyDataSetChanged()，如果您更改mHasBefore回其原始值，则需要再次调用。

于 2013-06-14T12:11:55.020 回答
-2

在 ListView 上使用 HeaderView 和 FooterView 怎么样？

这样，您就不必处理多种类型...

于 2013-06-14T12:37:35.793 回答