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我在将 Python 2.7 超级简单脚本冻结为独立应用程序时遇到了问题。

我使用 Spynner 完全没有问题，但是当我尝试冻结我的超级简单脚本时：

from spynner import *

在 CMD 中打开“test.exe”时出现以下错误：

C:\Python27\Scripts\MY\build\exe.win32-2.7>test.exe
Traceback (most recent call last):
  File "C:\Python27\lib\site-packages\cx_Freeze\initscripts\Console.py", li
    exec code in m.__dict__
  File "test.py", line 1, in <module>
  File "C:\Python27\lib\site-packages\spynner-2.4-py2.7.egg\spynner\__init_
    from browser import *
  File "C:\Python27\lib\site-packages\spynner-2.4-py2.7.egg\spynner\browser
    class Browser(object):
  File "C:\Python27\lib\site-packages\spynner-2.4-py2.7.egg\spynner\browser
    pkg_resources.resource_filename('spynner', 'javascript'),
  File "build/bdist.linux-i686/egg/pkg_resources.py", line 882, in resource
  File "build/bdist.linux-i686/egg/pkg_resources.py", line 1344, in get_res
NotImplementedError: resource_filename() only supported for .egg, not .zip

提前感谢您的任何想法。

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1 回答 1

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我有同样的问题，我解决了，分享我的解决方案，
我更改 spynner 模块源代码“browser.py”第 77 行

class Browser(object):
    """
    Stateful programmatic web browser class based upon QtWebKit.
    """
    errorCode = None
    errorMessage = None
    if hasattr(sys, "frozen"):
        Handle_Frozen_Location = os.path.join(os.path.dirname(sys.executable), 'javascript')
    else:
        Handle_Frozen_Location = pkg_resources.resource_filename('spynner', 'javascript')
    _javascript_directories = [Handle_Frozen_Location, ]
    _jquery = 'jquery-1.5.2.js'
    _jquery_simulate = 'jquery.simulate.js'
#.....# all the same

比将 javascript 文件夹从C:\Python27\Lib\site-packages\spynner-2.15-py2.7.egg\spynner
（上面是 Windows 路径...）
复制到您的构建文件夹中，如c:\somewhere\build\exe .win32-2.7
希望能解决你的问题...

于 2013-08-22T06:40:19.860 回答