javascript - Regex Matching - Content within brackets

Question

This is a fast question, I just don't know many Regex tricks and can't find documentation for this exact point:

Lets say I have the string:

'I know [foo] and [bar] about Regex'

I want to do a JS Regex pattern that makes an array of each bracket encapsulation. Result:

['[foo]', '[bar]']

I currently have:

str.match(/\[(.*)\]/g);

But this returns:

'[foo] and [bar]'

Thanks.

Answer 1

str.match(/\[(.*?)\]/g);

使用?修饰符使*量词非贪婪。非贪婪量词将匹配可能的最短字符串而不是最长字符串，这是默认值。

Answer 2

改用这个：

var str = 'I know [foo] and [bar] about Regex';
str.match(/\[([^\[\]]*)\]/g);

您的正则表达式部分错误是因为(.*)，这使您的模式允许and之间的任何字符，其中包括and 。[][]

Answer 3

尝试

var array = 'I know [foo] and [bar] about Regex'.match(/(\[[^\]]+\])/g)

Answer 4

改用这个：

\\[[^\\]]+\\]

您的正则表达式部分错误是因为(.*)，这使您的模式允许 and 之间的任何字符[，]其中包括[and ]。