我收到以下错误
您的 SQL 语法有错误;检查与您的 MySQL 服务器版本相对应的手册,以在第 114 行的 '' 附近使用正确的语法
但我的代码只有 27 行
<?php
$DB_NAME = 'QCSYSTEM';
$DB_HOST = 'monitor';
$DB_USER = 'QCSYSTEM';
$DB_PASS = '247#Direct';
$mysqli = new mysqli($DB_HOST, $DB_USER, $DB_PASS, $DB_NAME);
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
// A QUICK QUERY ON A FAKE USER TABLE
$query = "SELECT username FROM `users` WHERE";
$result = $mysqli->query($query) or die($mysqli->error.__LINE__);
// GOING THROUGH THE DATA
if($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
echo stripslashes($row['username']);
}
}
else {
echo 'NO RESULTS';
}
// CLOSE CONNECTION
mysqli_close($mysqli);
?>