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考虑以下伪代码:
func1(): func2() #func2 is called inside func1
我的问题是,在 func2 中我可以访问调用它的函数的名称吗?在这种情况下,func1? 谢谢!
import inspect def func2(): cframe = inspect.currentframe() func = inspect.getframeinfo(cframe.f_back).function print 'called from ' + func def func1(): func2() func2() func1()
输出:
called from <module> called from func1