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我收到了一些这样的 xml:

<cite id="0ac50429-bfbd-74e5-81bf-be29583cba3b">
<cite id="0ac50429-bfbd-74e5-81bf-be2a36aec2df">
<cite id="0ac50429-bfbd-74e5-81bf-be3d125bdc1c">Some Text
</cite>
</cite>
</cite>
<p>random text</p>
<cite id="0ac50429-bfbd-74e5-81bf-be29583cba3b">
<cite id="0ac50429-bfbd-74e5-81bf-be2a36aec2df">
<cite id="0ac50429-bfbd-74e5-81bf-be3d125bdc1c">
More text
</cite>
</cite>
</cite>

如您所见,对于相同的值,我有超过 1 个标签,而每个文本只需要 1 个标签:

<cite id="0ac50429-bfbd-74e5-81bf-be3d125bdc1c">Some Text</cite>
<p>random text</p>
<cite id="0ac50429-bfbd-74e5-81bf-be29583cba3b">More text</cite>

但我找不到摆脱这种情况的好方法。有人有线索吗?我试图得到最后一个孩子,但我就是无法得到他们。我已经尝试过使用正则表达式,我可以获得最后一个节点,但我无法正确替换它们,以获得所需的 xml。泰!

这是我的解决方案(我无法回答我自己的问题,所以我把它写在这里:)

我知道这不是最好的,可以做得更好,它有效。

private static String replaceNodes(String simpleRegex, String xml)
{

    String tagMultiple;
    String expresionRegular = "("+simpleRegex+")+";

    Pattern pattern = Pattern.compile(expresionRegular);
    Matcher matcher = pattern.matcher(xml);


    while(matcher.find())  // Here we look for all the nodes that are repeated . EJ  <cite id="asda"><cite id="asda"><cite id="asda">
    {
         Pattern patternSimple = Pattern.compile(simpleRegex);
        Matcher matcherSimple = patternSimple.matcher(xml);
        String tagUnicoEnd ="";
        if (matcherSimple.find()) //Here we get only one node. <cite id="asda">
            tagUnicoEnd = matcher.group(1);         

        tagMultiple = matcher.group();                  
        xml =xml.replace(tagMultiple,tagUnicoEnd);  //we replace all the repetead nodes, with the unique one.
    }       

    return xml;                         
}
4

1 回答 1

0

最后我找到了一种方法,我知道这不是最好的,可以做得更好

private static String replaceNodes(String simpleRegex, String xml)
{

    String tagMultiple;
    String expresionRegular = "("+simpleRegex+")+";

    Pattern pattern = Pattern.compile(expresionRegular);
    Matcher matcher = pattern.matcher(xml);


    while(matcher.find())  // Here we look for all the nodes that are repeated . EJ  <cite id="asda"><cite id="asda"><cite id="asda">
    {
         Pattern patternSimple = Pattern.compile(simpleRegex);
        Matcher matcherSimple = patternSimple.matcher(xml);
        String tagUnicoEnd ="";
        if (matcherSimple.find()) //Here we get only one node. <cite id="asda">
            tagUnicoEnd = matcher.group(1);         

        tagMultiple = matcher.group();                  
        xml =xml.replace(tagMultiple,tagUnicoEnd);  //we replace all the repetead nodes, with the unique one.
    }       

    return xml;                         
}
于 2013-06-14T13:07:38.657 回答