我正在尝试使用 Django ORM 对我的 bd 进行查询,但我需要一些帮助。
楷模:
class Participant(models.Model):
username = models.CharField(max_length=20)
username.primary_key = True
#password = models.CharField(max_length=128)
work_place = models.CharField(max_length=50)
photo = models.FileField(upload_to='user_photo')
name = models.CharField(max_length=30)
country = models.CharField(max_length=20)
phone_number = models.IntegerField(max_length=9)
email = models.EmailField(unique = True)
qrcode = models.FileField(upload_to = 'qrcodes',null=True,blank=True)
contact = models.OneToOneField('Contact', related_name= 'participant_contact')
user = models.OneToOneField(User)
contacts = models.ManyToManyField('Contact', related_name='contact_list', null=True, blank=True)
def save( self, *args, **kw ):
self.username = self.user.username
c= Contact()
c.save()
self.contact = c
super( Participant, self ).save( *args, **kw )
def __unicode__(self):
return self.username
class Contact(models.Model):
id = models.AutoField(primary_key=True)
我需要获取作为给定参与者的联系人的所有参与者
例子:
Contact Table: | id |
|_______|
| 1 |
| 2 |
Participant Table: |username|...|participant_contact|
|_______ |___|___________________|
| test | | 1 |
| test2 | | 2 |
Contacts Relation: |id_Participant1|id_participant_2|
|_______________|________________|
| 1 | 2 |
> p1 = Participant.objects.get(username="test")
> p2 = Participant.objects.get(username="test2")
p2
在p1
联系人列表中也是如此。如何使用 django ORM 进行此查询?