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SELECT a.id,
       a.username,
       a.email,
       a.created,
       b.user_id,
       SUM(b.price) + 
       SUM(IF(d.beginner =0, 15, 0)) + CASE WHEN SUM(b.price) >499 THEN 100
                                            ELSE 0 END AS points,
       SUM(b.price) AS pris,
       b.created,
       c.user_id,
       c.referrer_id,
       c.created,
       d.id,
       d.beginner,
       d.winner_id
FROM users a,
     accounts b,
     referrals c,
     product d
WHERE a.created BETWEEN '2013-04-01' AND '2013-06-30'
  AND d.created BETWEEN '2013-06-01' AND '2013-06-30'
  AND b.created BETWEEN '2013-06-01' AND '2013-06-30'
  AND a.id = b.user_id
  AND a.id = c.user_id
  AND d.winner_id = a.id
GROUP BY c.referrer_id
ORDER BY `points` DESC LIMIT 0 , 3

在这个查询中，我有四个表。对于product表格，我希望它也可以根据created. 但是当我喜欢我在查询中所做的事情时，它并没有给我正确的结果。我也想用这个查询选择产品表，条件是我只需要选择从 6 月 1 日到 6 月 30 日的记录，并根据如果在产品表中找到获胜者将增加 15 分的条件放置它们。

如果您看到此SUM( IF( d.beginner =0, 15, 0 ) )条件，如果我不添加AND d.created BETWEEN '2013-06-01' AND '2013-06-30'并且如果用户未在产品表中找到但在其余两个条件中具有例如 30 点之类的点，则它不会在此查询中显示。我不知道为什么？我希望在 6 月 1 日至 6 月 30 日期间选择产品和帐户表，并在 4 月 1 日至 6 月 30 日期间选择表用户

    SELECT a.id, a.username, a.email, a.created, b.user_id, SUM( b.price ) + 
CASE WHEN SUM( b.price ) >499
THEN 100 
ELSE 0 
END AS gr, SUM( b.price ) AS pris, b.created, c.user_id, c.referrer_id, c.created
FROM users a, accounts b, referrals c
WHERE a.created
BETWEEN  '2013-04-01'
AND  '2013-06-30'
AND b.created
BETWEEN  '2013-06-01'
AND  '2013-06-30'
AND a.id = b.user_id
AND a.id = c.user_id
GROUP BY c.referrer_id
ORDER BY  `gr` DESC 
LIMIT 0 , 3

我现在已经从这里删除了产品表条件。所以现在很容易理解。我想添加表products，其中仅从 6 月 1 日到 30 日选择行，第二个条件是如果用户在winner_id列中的产品表中找到，则添加 15 分。

4

1 回答 1

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Your comments suggest no record is found on the product table in that range. If you still want a row brought back in such a situation then use a LEFT OUTER JOIN. Something like as follows:-

SELECT a.id,
       a.username,
       a.email,
       a.created,
       b.user_id,
       SUM(b.price) + 
       SUM(CASE WHEN d.beginner IS NULL THEN 0 WHEN d.beginner = 0 THEN 15 ELSE 0 END) + CASE WHEN SUM(b.price) >499 THEN 100
                                            ELSE 0 END AS points,
       SUM(b.price) AS pris,
       b.created,
       c.user_id,
       c.referrer_id,
       c.created,
       d.id,
       d.beginner,
       d.winner_id
FROM users a
INNER JOIN accounts b ON a.id = b.user_id
INNER JOIN referrals c ON a.id = c.user_id
LEFT OUTER JOIN product d ON d.winner_id = a.id AND d.created BETWEEN '2013-06-01' AND '2013-06-30'
WHERE a.created BETWEEN '2013-04-01' AND '2013-06-30'
  AND b.created BETWEEN '2013-06-01' AND '2013-06-30'
GROUP BY c.referrer_id
ORDER BY `points` DESC 
LIMIT 0 , 3
于 2013-06-14T13:06:44.443 回答