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我正在尝试将 MySQL 查询结果导出到远程 ftp 服务器。

我有以下代码，但目前出现错误：

Warning: ftp_put() [function.ftp-put]: Opening ASCII mode data connection. in /home/hulamyxr/public_html/kisv2/xmltest/export.php on line 50

我认为我$file = $csv_filename;可能是问题所在，因为这是获取刚刚在我的本地服务器上创建的 csv 文件？

有任何想法吗？

我的语法是：

<?php
$host = 'localhost';
$user = 'un';
$pass = 'pwd';
$db = 'dbname';
$table = 'v2ReportingTable';
$file = 'export';
$datetime=date("Y-m-d H:i:s");
$link = mysql_connect($host, $user, $pass) or die("Can not connect." . mysql_error());

//Create a CSV for 
$result = mysql_query("SELECT * FROM dbname.v2ReportingTable"); 
if (!$result) die('Couldn\'t fetch records'); 
$num_fields = mysql_num_fields($result); 
$headers = array(); 
for ($i = 0; $i < $num_fields; $i++) 
{     
       $headers[] = mysql_field_name($result , $i); 
} 
$csv_filename = "export-" .$datetime.".csv";
$fp = fopen($csv_filename, 'w+');


if ($fp && $result) 
{
    fputcsv($fp, $headers);
    while ($row = mysql_fetch_row($result)) 
    {
        fputcsv($fp, array_values($row)); 
    }
}

//works till here

$ftp_server = "ftp.server.co.za";
$ftp_user_name = "un";
$ftp_user_pass = "pw";
$file = $csv_filename;
$remote_file = "/LocExports/".$file;


// set up basic connection
$conn_id = ftp_connect($ftp_server);

// login with username and password
$login_result = ftp_login($conn_id, $ftp_user_name, $ftp_user_pass);

// upload a file
if (ftp_put($conn_id, $remote_file, $file, FTP_ASCII)) {
 echo "successfully uploaded $file\n";
} else {
 echo "There was a problem while uploading $file\n";
}

// close the connection
ftp_close($conn_id);
?>

再次感谢

4

1 回答 1

1

它在正确的位置创建文件，但它是一个 0kb 文件，此后所有 FTP 命令都失败。客户端很可能位于防火墙后面。要纠正这种使用：

<?php

ftp_pasv($resource, true);

?>
于 2013-06-13T14:34:18.827 回答