我已经搜索了几个小时的董事会，所以请不要有刻薄的答案。
以下不会从 jQuery 调用我的表单处理程序
<body>
<h1>Request A Consultation</h1>
<form id="consult_request" name="consult_request" method="post" action="">
<table width="500" border="0" cellspacing="5" cellpadding="0">
<tr>
<td width="132"><label for="firstName">First Name</label></td>
<td width="353"><input type="text" name="firstName" id="firstName" class="input required" /></td>
</tr>
<tr>
<td><label for="lastName">Last Name</label></td>
<td><input type="text" name="lastName" id="lastName" class="input required" /></td>
</tr>
<tr>
<td><label for="emailAddress">Email Address</label></td>
<td><input type="email" name="emailAddress" id="emailAddress" class="input required" /></td>
</tr>
<tr>
<td><label for="emailConfirm">Verify Email Address</label></td>
<td><input type="email" name="emailConfirm" id="emailConfirm" class="input required" equalTo="#emailAddress" /></td>
</tr>
<tr>
<td> </td>
<td><input type="submit" name="button" id="button" value="Send Request »" class="button" /></td>
</tr>
</table>
</form>
<script>
$('#consult_request').validate({
submitHandler: function(form){
jQuery(form).ajaxSubmit({url: '/_interface/process/testvars.asp', type: 'post'});
}
});
</script>
</body>
</html>
注意：我只使用布局表，因为它是遗留代码。我自己更了解。
我的表格在 /_interface/content/popups/request.asp