11

我很确定我在这里做错了很多事情，但我不确定是什么......

该表（减去几个字段）：

CREATE TABLE IF NOT EXISTS `stuff` (
  `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `lat` decimal(12,7) NOT NULL,
  `lon` decimal(12,7) NOT NULL,
  `location` point NOT NULL,  
  UNIQUE KEY `id` (`id`),
  KEY `distance` (`distance`),
  KEY `lat` (`lat`),
  KEY `lon` (`lon`),
  SPATIAL KEY `location` (`location`)
) ENGINE=MyISAM  DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=5;

自动设置定位点的触发器：

DROP TRIGGER IF EXISTS `stuff_insert_defaults`;
DELIMITER //
CREATE TRIGGER `stuff_insert_defaults` BEFORE INSERT ON `stuff`
 FOR EACH ROW SET NEW.location = PointFromText(CONCAT('POINT(',NEW.lat,' ',NEW.lon,')'))
//
DELIMITER ;

DROP TRIGGER IF EXISTS `stuff_update_location`;
DELIMITER //
CREATE TRIGGER `stuff_update_location` BEFORE UPDATE ON `stuff`
 FOR EACH ROW SET NEW.location = PointFromText(CONCAT('POINT(',NEW.lat,' ',NEW.lon,')'))
//
DELIMITER ;

一些样本数据（科罗拉多州内的 4 个随机点）：

/* 4 random points within the state of colorado */
INSERT INTO `stuff` (`id`, `distance`, `lat`, `lon`, `location`) VALUES
(1, 5.0000000, 40.2488450, -103.8003460, 0x000000000101000000f6622827da1f444001df6dde38f359c0),
(2, 5.0000000, 38.4849180, -107.8726700, 0x000000000101000000f19e03cb113e4340d28c45d3d9f75ac0),
(3, 5.0000000, 39.5040250, -105.3584800, 0x000000000101000000e6ae25e483c0434049111956f1565ac0),
(4, 5.0000000, 39.1904180, -106.8179680, 0x000000000101000000ed48f59d5f9843402b4b749659b45ac0);

科罗拉多州的粗略外部边界：

NW corner: 41.000497 -109.050149 
NE corner: 41.002380 -102.051881 
SE corner: 36.993237 -102.041959 
SW corner: 36.999037 -109.045220

应该返回我们插入的 4 条记录的查询：

SELECT *, AsText(location) FROM stuff 
 WHERE Contains(
 GeomFromText('POLYGON((41.000497 -109.050149, 41.002380 -102.051881, 36.993237 -102.041959, 36.999037 -109.045220, 41.000497 -109.050149))'), location );

我要回什么...

nada... 
zip... 
nil... 
nothing...
4

1 回答 1

11

如ClassPolygon下所述（强调添加）：

Polygon断言

  • a 的边界由构成其外部和内部边界Polygon的一组LinearRing对象（即LineString既简单又封闭的对象）组成。

因此，您必须通过在起点完成来关闭多边形：

SELECT *, AsText(location) FROM stuff 
 WHERE Contains(
 GeomFromText('POLYGON((41.000497 -109.050149, 41.002380 -102.051881, 36.993237 -102.041959, 36.999037 -109.045220, 41.000497 -109.050149))'), location );

在sqlfiddle上查看。

于 2013-06-12T19:47:16.103 回答