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我正在构建一个网络应用程序,并且我正在尝试使用谷歌地图在地图上显示多个标记,如果您运行我的代码,您将看到地图上显示多个标记,延迟 3 秒。

我想要实现的是让一个标记出现 3 秒,然后(消失!!!)在下一个出现之前谢谢你的帮助

这是我的代码\

 <!DOCTYPE html>
<html>
  <head>
    <meta name="viewport" content="initial-scale=1.0, user-scalable=no">
    <meta charset="utf-8">
    <title>Map</title>

    <script src="https://maps.googleapis.com/maps/api/js?v=3.exp&sensor=false"></script>
    <script>
function initialize() {
//create a roadmap centered around specific coordinates
  var mapOptions = {
    zoom: 4,
    center: new google.maps.LatLng(44.645636,-63.576679),
    mapTypeId: google.maps.MapTypeId.ROADMAP
  };
//creates the map with size and boundries as defined by element id
  var map = new google.maps.Map(document.getElementById('map-canvas'),
      mapOptions);

  // Specify the bounds of the location
  var southWest = new google.maps.LatLng(44.649391,-63.584747);
  var northEast = new google.maps.LatLng(44.645636,-63.576679);

  var bounds = new google.maps.LatLngBounds(southWest, northEast);
  map.fitBounds(bounds);

  var lngSpan = northEast.lng() - southWest.lng();
  var latSpan = northEast.lat() - southWest.lat();
var i =0; //  set your counter to 0
function myLoop(){ //  create a loop function
setTimeout(function(){ //  call a 3s setTimeout when the loop is called
  //creates random location around area bounded by southwest & Northwest coordinates

    var position = new google.maps.LatLng(
        southWest.lat() + latSpan * Math.random(),
        southWest.lng() + lngSpan * Math.random())
    var marker = new google.maps.Marker({
      position: position,
      map: map
    });

    i++;//  increment the counter

    if(i<6){myLoop();}//  if the counter < 10, call the loop function
  },3000)
  }
  myLoop();//  start the loop
}

}
google.maps.event.addDomListener(window, 'load', initialize);
    </script>
  </head>
  <body >

    <div id="map-canvas"style="width: 100%; height: 100%; position: absolute;"></div>
  </body>
</html>
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1 回答 1

1

跟踪您添加的最后一个标记。

您可以在一个数组或一个变量中跟踪您的标记。

然后在添加新标记之前,请确保隐藏之前的标记

于 2013-06-12T15:12:03.027 回答