我的项目的重点是创建一个交互式教程。我正在播放声音剪辑，并且在声音剪辑期间的某些时候，我希望执行某些操作（例如，突出显示按钮）。我想出了一个解决方案，但我觉得它占用了很多 CPU。我想出的解决方案是为声音剪辑期间将发生的每个单独动作设置每个单独的计时器。如果我开始为 50 个不同的动作制作 50 个不同的计时器，这会产生 50 个不同的线程，我预计最终会在 CPU 上出现这种情况。
这是我当前使用这些计时器的代码片段；
private void Label_FindingPart_MouseDoubleClick(object sender, MouseButtonEventArgs e)
{
sound.Source = new Uri(@"C:\SomeSound.wav");
sound.Position = TimeSpan.Zero;
sound.Play();
Timer_Logistics_Button(1000);
Timer_Logistics_Window(1500);
Timer_MMBE_Button(2000);
Timer_MMBE_Window(2500);
}
//Timer initalized
private void Timer_Logistics_Button(int interval_length)
{
System.Timers.Timer aTimer = new System.Timers.Timer();
aTimer.AutoReset = false;
aTimer.Elapsed += new ElapsedEventHandler(On_Timer_Logistics_Button);
aTimer.Interval = interval_length;
aTimer.Enabled = true;
}
//Action when the Elapsed event is raised.
private void On_Timer_Logistics_Button(object source, ElapsedEventArgs e)
{
Dispatcher.BeginInvoke((Action)delegate()
{
Button_Logistics.Visibility = Visibility.Visible;
});
}
//Timer initalized
private void Timer_Logistics_Window(int interval_length)
{
System.Timers.Timer aTimer = new System.Timers.Timer();
aTimer.AutoReset = false;
aTimer.Elapsed += new ElapsedEventHandler(On_Timer_Logistics_Window);
aTimer.Interval = interval_length;
aTimer.Enabled = true;
}
//Action when the Elapsed event is raised.
private void On_Timer_Logistics_Window(object source, ElapsedEventArgs e)
{
Dispatcher.BeginInvoke((Action)delegate()
{
Image_SAP_Main.Visibility = Visibility.Hidden;
Image_SAP_Main_Logistics.Visibility = Visibility.Visible;
Button_Logistics.Visibility = Visibility.Hidden;
});
}
//Timer initalized
private void Timer_MMBE_Button(int interval_length)
{
System.Timers.Timer bTimer = new System.Timers.Timer();
bTimer.AutoReset = false;
bTimer.Elapsed += new ElapsedEventHandler(On_Timer_MMBE_Button);
bTimer.Interval = interval_length;
bTimer.Enabled = true;
}
//Action when the Elapsed event is raised.
private void On_Timer_MMBE_Button(object source, ElapsedEventArgs e)
{
Dispatcher.BeginInvoke((Action)delegate()
{
Button_MMBE.Visibility = Visibility.Visible;
});
}
//Timer initalized
private void Timer_MMBE_Window(int interval_length)
{
System.Timers.Timer bTimer = new System.Timers.Timer();
bTimer.AutoReset = false;
bTimer.Elapsed += new ElapsedEventHandler(On_Timer_MMBE_Window);
bTimer.Interval = interval_length;
bTimer.Enabled = true;
}
//Action when the Elapsed event is raised.
private void On_Timer_MMBE_Window(object source, ElapsedEventArgs e)
{
Dispatcher.BeginInvoke((Action)delegate()
{
Image_SAP_Main_Logistics.Visibility = Visibility.Hidden;
Button_MMBE.Visibility = Visibility.Hidden;
Image_SAP_MMBE.Visibility = Visibility.Visible;
});
}
我的另一个想法是创建一个线程并让它与 sound.play() 同时启动。这个线程将有多个 thread.sleep() 语句用于每个操作之间的等待时间。所以回想起来，它看起来像这样：
Step A: Play();
Step B: Thread.Start();
Step C: Thread.sleep(1000);
Step D: ACTION;
Step E: Thread.sleep(500);
Step F: ACTION;
Step G: Thread.sleep(1200);
Step H: ACTION;
Step I: Thread.Stop();
下面的代码是我所能得到的线程，我很难从步骤 D 到步骤 E。我还需要找出如何正确停止我的线程。下面的代码是我能够溃烂的：
System.Threading.Thread Tutorial_Thread = new System.Threading.Thread(new System.Threading.ThreadStart(
delegate()
{
// Do the work here.
Thread.Sleep(5000);
this.Dispatcher.BeginInvoke(new Action(
delegate()
{
// Invoke any updates to the GUI here.
Button_Logistics.Visibility = Visibility.Visible;
}
));
}
));
sound.Play();
Tutorial_Thread.Start();
一旦线程通过，它将返回到线程的开头并执行 thread.sleep(5000)。我不确定如何通过线程更改每次旋转的睡眠时间和动作。任何帮助将不胜感激，我希望我的问题清晰易懂。我正在使用 Visual Studio 2012、C#、WPF。