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我在这里有点进退两难。

我有一个评论脚手架和一个电影脚手架

当转到电影页面并创建新评论时,我去这里 /movies/12/comments/new (12 是 id)

做的是我的控制器

def new
    @movie = Movie.find(params[:movie_id])
    @comment = @movie.comments.new 
    @search = Movie.search(params[:q])

    respond_to do |format|
      format.html # new.html.erb
      format.json { render json: @comment }
    end
  end

但是当我启动到heroku时,我得到了这个错误

*Processing by CommentsController#new as HTML
 ActiveRecord::StatementInvalid (PG::Error: ERROR:  invalid input syntax for integer: "movie_id"

 Completed 500 Internal Server Error in 636ms
LINE 1: ...  "movies".* FROM "movies"  WHERE "movies"."id" = 'movie_id'...

Parameters: {"movie_id"=>"the-social-network"}
app/controllers/comments_controller.rb:99:in `load_movie'*

我尝试在最后删除@movie = Movie.find(params[:movie_id])或添加.to_i,如此处所述为什么 Rails 中的 this :id 不适用于 Postgresql 但它确实适用于 MySQL?,但仍然没有运气

有任何想法吗?谢谢!

Comment_form (查看)

<%= simple_form_for(@comment) do |f| %>
  <%= f.error_notification %>

  <div class="form-inputs">
    <%= f.input :subject %>
    <%= f.input :body %>
    <%= f.input :movie_id %>
  </div>

  <div class="form-actions">
    <%= f.button :submit %>
  </div>
<% end %>

电影.rb

class Movie < ActiveRecord::Base
  attr_accessible :title


 has_many :comments, :dependent => :destroy

      extend FriendlyId
  friendly_id :titleyear, use: :history
  def titleyear
    "#{title} #{id}"
  end

end

评论.rb

class Comment < ActiveRecord::Base
  attr_accessible :body, :movie_id, :subject, :user_id

  belongs_to :user
  belongs_to :movie




end

Comments_controller.rb

class CommentsController < ApplicationController
  # GET /comments
  # GET /comments.json
  before_filter :load_movie
  before_filter :authenticate_user!, only: [:new,:create,:edit,:destroy]



  def index
    @comments = @movie.comments.all
    @search = Movie.search(params[:q])

    respond_to do |format|
      format.html # index.html.erb
      format.json { render json: @comments }
    end
  end

  # GET /comments/1
  # GET /comments/1.json
  def show
    @comment = Comment.find(params[:id])
    @search = Movie.search(params[:q])

    respond_to do |format|
      format.html # show.html.erb
      format.json { render json: @comment }
    end
  end

  # GET /comments/new
  # GET /comments/new.json
  def new
    @movie = Movie.find(params[:movie_id])
    @comment = @movie.comments.new 
    @search = Movie.search(params[:q])

    respond_to do |format|
      format.html # new.html.erb
      format.json { render json: @comment }
    end
  end

  # GET /comments/1/edit
  def edit
    @comment = Comment.find(params[:id])
    @search = Movie.search(params[:q])

  end

  # POST /comments
  # POST /comments.json
  def create
    @comment = Comment.new(params[:comment])
    @search = Movie.search(params[:q])

    respond_to do |format|
      if @comment.save
        format.html { redirect_to :back }
        format.json { render json: @comment, status: :created, location: @comment }
      else
        format.html { render action: "new" }
        format.json { render json: @comment.errors, status: :unprocessable_entity }
      end
    end
  end

  # PUT /comments/1
  # PUT /comments/1.json
  def update
    @comment = Comment.find(params[:id])
    @search = Movie.search(params[:q])

    respond_to do |format|
      if @comment.update_attributes(params[:comment])
        format.html { redirect_to (@movie), notice: 'Comment was successfully updated.' }
        format.json { head :no_content }
      else
        format.html { render action: "edit" }
        format.json { render json: @comment.errors, status: :unprocessable_entity }
      end
    end
  end

  # DELETE /comments/1
  # DELETE /comments/1.json
  def destroy
    @comment = Comment.find(params[:id])
    @comment.destroy

    respond_to do |format|
      format.html { redirect_to comments_url }
      format.json { head :no_content }
    end
  end

private
    def load_movie
      @movie = Movie.find_by_id(:movie_id)
    end


end
4

1 回答 1

2

movie_id当您传递它时,该参数实际上不是一个id,而是一个字符串:Parameters: {"movie_id"=>"the-social-network"}

在您看来,某些东西可能配置错误。确保您通过的是movie.id而不是其他东西。

编辑:

收到的错误表明该字符串the-social-network是从movie_idURL 段传递的。您需要通过访问将数字作为第二个参数传递的路径来访问您的表单,例如http://yoursite/movies/2/comments/new,而不是http://yoursite/movies/the-social-network/comments/new

于 2013-06-11T20:59:06.823 回答