1

我有一张像这样的桌子：

logID   eventID repID   statusID    logTime
174356  228985  107959  1           2013-05-03 09:25:41.000
174391  228985  107959  1           2013-05-03 10:06:33.000
174588  228985  107959  2           2013-05-03 14:59:51.000

我希望输出为

Date    ClockIn         ClockOut
05/03/2013  9:25:41 AM  
05/03/2013  10:06:33 AM 2:59:51 PM

即.. 如果状态为 1，则必须在 ClockIn 中，如果为 2，则在 ClockOut 中。

但我得到的输出为

Date    ClockIn         ClockOut
05/03/2013  9:25:41 AM  2:59:51 PM
05/03/2013  10:06:33 AM 2:59:51 PM

我已经检查了状态是否为 2，如果它大于时钟时间，那么它必须显示在时钟下班时间...

我的查询：

Select LTRIM(RIGHT(CONVERT(CHAR(20), rt.logTime, 22), 11)) as ClockIn, 
LTRIM(RIGHT(CONVERT(CHAR(20), Min(rt1.logTime), 22), 11)) as ClockOut
from table1 rt
join table1  rt1  ON rt.repID = rt1.repID and rt1.statusID=2 
AND CONVERT(nvarchar(25), rt.logTime,101) = CONVERT(nvarchar(25), rt1.logTime,101) AND rt.logTime<rt1.logTime
where rt.eventID='228985' and rt.repID='107959' and CONVERT(date, rt.logTime) = CONVERT(date, '05/03/2013')
group by rt.logTime, rt1.logTime

我应该如何得到想要的结果…………

4

1 回答 1

1

试试这个答案。

    SELECT LTRIM(RIGHT(CONVERT(CHAR(20), rt.logTime, 22), 11)) AS ClockIn,
    LTRIM(RIGHT(CONVERT(CHAR(20), Min(rt1.logTime), 22), 11)) AS ClockOut
FROM table1 rt
LEFT JOIN (
    SELECT eventID,
        repID,
        CONVERT(DATE, logTime) LogTime,
        MAX(logId) LogID
    FROM table1
    WHERE StatusID = 1
    GROUP BY eventID,
        repID,
        CONVERT(DATE, logTime)
    ) rr
    ON rt.LogId = rr.logId
LEFT JOIN table1 rt1
    ON rr.repID = rt1.repID
        AND rt1.statusID = 2
        AND CONVERT(NVARCHAR(25), rr.logTime, 101) = CONVERT(NVARCHAR(25), rt1.logTime, 101)
        AND rt.logTime < rt1.logTime
WHERE rt.StatusID = 1
    AND rt.eventID = '228985'
    AND rt.repID = '107959'
    AND CONVERT(DATE, rt.logTime) = CONVERT(DATE, '05/03/2013')
GROUP BY rt.logTime,
    rt1.logTime

小提琴演示

于 2013-06-11T12:12:42.067 回答