3

我有三个下拉菜单。我希望当用户从下拉列表 1 中选择任何项目时，应在下拉列表 2 和 3 中禁用该项目。此外，如果在下拉列表 2 中选择了一个项目，则必须从下拉列表 3 中禁用两个选定项目。

这是我正在使用的代码：

<!DOCTYPE html>
<html>
<head>
  <script>
    function updateSelect(changedSelect, selectId) {
      var otherSelect = document.getElementById(selectId);
      for (var i = 0; i < otherSelect.options.length; ++i) {
        otherSelect.options[i].disabled = false;
      }
      if (changedSelect.selectedIndex == 0) {
        return;
      }
      otherSelect.options[changedSelect.selectedIndex].disabled = true;
    }
  </script>
</head>
<body>
  <select id="select_1"  onchange="updateSelect(this,'select_2'),updateSelect(this,'select_3');"   name="indication_subject[]">
    <option value="" selected="selected">a </option>
    <option value="1"> Accounting</option>
    <option value="2"> Afrikaans</option>
    <option value="3"> Applied Information and Communication Technology</option>
    <option value="4"> Arabic</option>
    <option value="5"> Art and Design</option>
    <option value="6"> Biology</option>
    <option value="7"> Business Studies</option>
  </select>
  <select id="select_2" name="indication_subject[]" onchange="updateSelect(this,'select_1','select_3');" >
    <option value="" selected="selected">a </option>
    <option value="1"> Accounting</option>
    <option value="2"> Afrikaans</option>
    <option value="3"> Applied Information and Communication Technology</option>
    <option value="4"> Arabic</option>
    <option value="5"> Art and Design</option>
    <option value="6"> Biology</option>
    <option value="7"> Business Studies</option>
  </select>
  <select id="select_3" name="indication_subject[]" onchange="updateSelect(this,'select_1','select_2');" >
    <option value="" selected="selected">a </option>
   <option value="1"> Accounting</option>
   <option value="2"> Afrikaans</option>
   <option value="3"> Applied Information and Communication Technology</option>
   <option value="4"> Arabic</option>
   <option value="5"> Art and Design</option>
   <option value="6"> Biology</option>
   <option value="7"> Business Studies</option>
  </select>
</body>
</html>

下面是适用于两个下拉菜单的 JSFiddle 链接，而不是三个。如何为此添加第三个下拉列表？

http://jsfiddle.net/x4E5Q/1/

4

3 回答 3

10

尝试这个：

HTML

<select id="select1" name="indication_subject[]">
  <option value="" selected="selected">a </option>
  <option value="1"> Accounting</option>
  <option value="2"> Afrikaans</option>
  <option value="3"> Applied Information and Communication Technology</option>
  <option value="4"> Arabic</option>
  <option value="5"> Art and Design</option>
  <option value="6"> Biology</option>
  <option value="7"> Business Studies</option>
</select>

<select id="select2" name="indication_subject[]">
  <option value="" selected="selected">a </option>
  <option value="1"> Accounting</option>
  <option value="2"> Afrikaans</option>
  <option value="3"> Applied Information and Communication Technology</option>
  <option value="4"> Arabic</option>
  <option value="5"> Art and Design</option>
  <option value="6"> Biology</option>
  <option value="7"> Business Studies</option>
</select>

<select id="select3" name="indication_subject[]">
  <option value="" selected="selected">a </option>
  <option value="1"> Accounting</option>
  <option value="2"> Afrikaans</option>
  <option value="3"> Applied Information and Communication Technology</option>
  <option value="4"> Arabic</option>
  <option value="5"> Art and Design</option>
  <option value="6"> Biology</option>
  <option value="7"> Business Studies</option>
</select>

JS

$(document).ready(function(){  
  $("select").change(function() {   
    $("select").not(this).find("option[value="+ $(this).val() + "]").attr('disabled', true);
  }); 
});

演示

于 2013-06-11T10:31:08.187 回答
0 
See below code

    $(document).ready(function() {
      $("select").on('hover', function () {
            $previousValue = $(this).val();
        }).change(function() {
            $("select").not(this).find("option[value='"+ $(this).val() + "']").attr('disabled', true);
            $("select").not(this).find("option[value='"+ $previousValue + "']").attr('disabled', false);
        });
    });

$("#confirm-form").submit(function(e) {
    e.preventDefault();
    $("select").find("option").removeAttr('disabled');
    document.getElementById('confirm-form').submit();
});
于 2017-08-03T08:20:06.683 回答
0 
$(document).ready(function(){  

  $("select").on('focus', function () {
        $("select").find("option[value='"+ $(this).val() + "']").attr('disabled', false);
    }).change(function() {

        $("select").not(this).find("option[value='"+ $(this).val() + "']").attr('disabled', true);

    });


});
于 2018-02-17T14:20:35.203 回答