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我想通过给出日期来获取一周中的日期列表。就像如果给出“2013 年 6 月 11 日”，我想将列表作为 PHP 数组，任何帮助将不胜感激

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3 回答 3

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我建议您在提问之前快速进行谷歌搜索，甚至在 StackOverflow 上进行搜索。正如 HamZa 在评论中所说 - SO 已经涵盖了关于日期的几乎所有内容。

您可以通过以下方式获得答案：

function week_from_monday($date) {
    // Assuming $date is in format DD-MM-YYYY
    list($day, $month, $year) = explode("-", $date);

    // Get the weekday of the given date
    $wkday = date('l',mktime('0','0','0', $month, $day, $year));

    switch($wkday) {
        case 'Monday': $numDaysToMon = 0; break;
        case 'Tuesday': $numDaysToMon = 1; break;
        case 'Wednesday': $numDaysToMon = 2; break;
        case 'Thursday': $numDaysToMon = 3; break;
        case 'Friday': $numDaysToMon = 4; break;
        case 'Saturday': $numDaysToMon = 5; break;
        case 'Sunday': $numDaysToMon = 6; break;   
    }

    // Timestamp of the monday for that week
    $monday = mktime('0','0','0', $month, $day-$numDaysToMon, $year);

    $seconds_in_a_day = 86400;

    // Get date for 7 days from Monday (inclusive)
    for($i=0; $i<7; $i++)
    {
        $dates[$i] = date('Y-m-d',$monday+($seconds_in_a_day*$i));
    }

    return $dates;
}

week_from_monday('07-10-2008') 的输出给出：

Array
(
    [0] => 2008-10-06
    [1] => 2008-10-07
    [2] => 2008-10-08
    [3] => 2008-10-09
    [4] => 2008-10-10
    [5] => 2008-10-11
    [6] => 2008-10-12
)

取自：在给定周数的情况下计算一周中的天数

于 2013-06-11T08:25:32.037 回答
1

DateTime类使这更简单：-

/**
 * Returns an array of date strings for the
 * week of the given date, starting on Monday
 *
 * @param String $date The date in question
 * @return array An array of date strings
 */
function daysInWeek($date)
{
    $result = array();
    $datetime = DateTime::createFromFormat('m/d/Y', $date);
    $interval = new DateInterval('P1D');
    if($datetime->format('D') !== 'Mon')$datetime->modify('last monday');
    $week = new DatePeriod($datetime, $interval, 6);
    foreach($week as $day){
        $result[] = $day->format('m/d/y');
    }
    return $result;
}

var_dump(daysInWeek("06/11/2013"));

回报：-

array (size=7)
  0 => string '06/10/13' (length=8)
  1 => string '06/11/13' (length=8)
  2 => string '06/12/13' (length=8)
  3 => string '06/13/13' (length=8)
  4 => string '06/14/13' (length=8)
  5 => string '06/15/13' (length=8)
  6 => string '06/16/13' (length=8)

这具有处理夏令时更改等的额外优势。

于 2013-06-11T08:57:13.327 回答
-1

您想获取与给定日期对应的日期的全名吗？如果是这样，您可以执行以下操作：

<?php
    echo date('l', strtotime('2013/11/06'));
?>
于 2013-06-11T08:24:50.360 回答