bash - 如何从 cygwin shell 脚本中的列表中回显字符串

Question

seven="( . 1 . 1 . 1)"
octal="zero one two three four five six seven"

for n in $octal
do
   echo $n
done

当它达到七时，它会回显“七”。你如何让它回( . 1 . 1 . 1)显哪个是字符串$seven？

Answer 1

seven="( . 1 . 1 . 1)"
octal="zero one two three four five six seven"

for n in $octal
do
   echo "${!n:-$n}"
done