我有一个接受多个图像的文件上传字段。我需要在上传这些图像之前预览它们。我还可以设置要上传的最大图像数量限制吗?
问问题
58181 次
4 回答
3
试试这个。 http://maraustria.wordpress.com/2014/04/25/multiple-select-and-preview-of-image-of-file-upload/
html
<label for=”files”>Select multiple files: </label>
<input id=”files” type=”file” multiple/>
<output id=”result” />
Javascript
window.onload = function(){
//Check File API support
if(window.File && window.FileList && window.FileReader)
{
var filesInput = document.getElementById(“files”);
filesInput.addEventListener(“change”, function(event){
var files = event.target.files; //FileList object
var output = document.getElementById(“result”);
for(var i = 0; i< files.length; i++)
{
var file = files[i];
//Only pics
if(!file.type.match(‘image’))
continue;
var picReader = new FileReader();
picReader.addEventListener(“load”,function(event){
var picFile = event.target;
var div = document.createElement(“div”);
div.innerHTML = “<img class=’thumbnail’ src=’” + picFile.result + “‘” +
“title=’” + picFile.name + “‘/>”;
output.insertBefore(div,null);
});
//Read the image
picReader.readAsDataURL(file);
}
});
}
else
{
console.log(“Your browser does not support File API”);
}
}
CSS
body{
font-family: ‘Segoe UI’;
font-size: 12pt;
}
header h1{
font-size:12pt;
color: #fff;
background-color: #1BA1E2;
padding: 20px;
}
article
{
width: 80%;
margin:auto;
margin-top:10px;
}
.thumbnail{
height: 100px;
margin: 10px;
}
于 2014-04-25T13:27:35.597 回答
1
有史以来最简单的解决方案。
HTML
<div class="measure-fld">
<input type="file" class="fileupload" name="room_imag[]" accept="image/x-png,image/gif,image/jpeg" required="">
<div class="dvPreview"></div>
</div>
JavaScript
jQuery(function() {
// Multiple images preview in browser
var imagesPreview = function(input, placeToInsertImagePreview) {
if (input.files) {
var filesAmount = input.files.length;
for (i = 0; i < filesAmount; i++) {
var reader = new FileReader();
reader.onload = function(event) {
$($.parseHTML('<img>')).attr('src', event.target.result).appendTo(placeToInsertImagePreview);
}
reader.readAsDataURL(input.files[i]);
}
}
};
jQuery(document).on('change','.fileupload',function() {
imagesPreview(this, 'div.dvPreview');
});
});
于 2019-03-08T05:59:38.770 回答
1
window.onload = function () {
var fileUpload = document.getElementById("fileupload");
fileUpload.onchange = function () {
if (typeof (FileReader) != "undefined") {
var dvPreview = document.getElementById("dvPreview");
dvPreview.innerHTML = "";
var regex = /^([a-zA-Z0-9\s_\\.\-:])+(.jpg|.jpeg|.gif|.png|.bmp)$/;
for (var i = 0; i < fileUpload.files.length; i++) {
var file = fileUpload.files[i];
if (regex.test(file.name.toLowerCase())) {
var reader = new FileReader();
reader.onload = function (e) {
var img = document.createElement("IMG");
var textbox = document.createElement('input');
textbox.type = 'text';
textbox.name = 'tag_line[]';
textbox.placeholder = 'Enter image tag line';
img.height = "100";
img.width = "100";
img.src = e.target.result;
dvPreview.appendChild(img);
dvPreview.appendChild(textbox);
}
reader.readAsDataURL(file);
} else {
alert(file.name + " is not a valid image file.");
dvPreview.innerHTML = "";
return false;
}
}
} else {
alert("This browser does not support HTML5 FileReader.");
}
}
};
<div class="row">
<div class="form-group col-sm-6">
<input id="fileupload" type="file" multiple="multiple" />
<hr />
<b>Preview</b><br />
</div>
</div>
<div id="dvPreview">
</div>
将此代码用于多个图像上传和文本框预览.....
于 2017-03-07T07:49:32.480 回答
0
HTML
<input type="file" id="multiupload" name="uploadFiledd[]" multiple >
<button type="button" id="upcvr" class="btn btn-primary">Start Upload</button>
<div id="uploadsts"></div>
脚本
<script>
function uploadajax(ttl,cl){
var fileList = $('#multiupload').prop("files");
$('#prog'+cl).removeClass('loading-prep').addClass('upload-image');
var form_data = "";
form_data = new FormData();
form_data.append("upload_image", fileList[cl]);
var imgData = new FileReader();
imgData.addEventListener('load',function(event){
var image = event.target;
$('#imgprv'+cl).attr('src',image.result);
});
imgData.readAsDataURL(fileList[cl]);
var request = $.ajax({
url: "upload.php",
cache: false,
contentType: false,
processData: false,
async: true,
data: form_data,
type: 'POST',
xhr: function() {
var xhr = $.ajaxSettings.xhr();
if(xhr.upload){
xhr.upload.addEventListener('progress', function(event){
var percent = 0;
if (event.lengthComputable) {
percent = Math.ceil(event.loaded / event.total * 100);
}
$('#prog'+cl).text(percent+'%')
}, false);
}
return xhr;
}
})
.success(function(res,status) {
if(status == 'success'){
percent = 0;
$('#prog'+cl).text('');
$('#prog'+cl).text('--Success: ');
if(cl < ttl){
uploadajax(ttl,cl+1);
}else{
alert('Done ');
}
}
})
.fail(function(res) {
alert(res.status+': '+res.statusText);
});
}
$('#upcvr').click(function(){
var fileList = $('#multiupload').prop("files");
$('#uploadsts').html('');
var i
for ( i = 0; i < fileList.length; i++) {
$('#uploadsts').append('<p class="upload-page"><img id="imgprv'+i+'" src="data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7" width="100px">'+fileList[i].name+'<span class="loading-prep" id="prog'+i+'"></span></p>');
if(i == fileList.length-1){
uploadajax(fileList.length-1,0);
}
}
});
</script>
PHP
upload.php
move_uploaded_file($_FILES["upload_image"]["tmp_name"],$_FILES["upload_image"]["name"]);
于 2018-08-04T10:46:26.557 回答