0

我尝试使用以下pl sql程序将我的表更新为field1，编译和执行没有任何错误，当我调用此程序时更新不起作用我不知道为什么！我使用for update of .... current of带有光标的 ( ) 语句，代码如下

create or replace procedure p1 is
r1 table1%rowtype;
r2 table2%rowtype;
cursor c1 is select * from table1 for update of field1;
cursor c2 is select * from table2;
begin
open c1;
loop <<outer>>
    fetch c1 into r1;
    open c2;
        loop <<inner>>
            fetch c2 into r2;
               if condition then
               dbms_output.put_line('ok');            
               update table1
               set field1= 1
               where current of c1;                    
               end if;
        exit when c2%notfound;
        end loop inner;       
    close c2; 
    exit when c1%notfound;
end loop outer;
close c1;
end;
/

注意：IF 语句中的条件是正确的，因为当我执行该过程时，dbms_output.put_line('ok');每次执行循环时，当我删除更新语句和 (for update of....current of) 语句时，语句 () 都会成功执行，但是当我将更新语句与 (for update of....current of) 语句放在相同的条件下，更新语句不起作用。

4

2 回答 2

2 
1)

    open c2;
        loop <<inner>>
            fetch c2 into r2;
               if condition then
               dbms_output.put_line('ok');            
               update table1
               set field1= 1
               where current of c1;  -- <---- YOU CANNOT USE THAT
               end if;
        exit when c2%notfound;
        end loop inner;       
    close c2; 

2) Rewrite to plain SQL:

CREATE TABLE table1(field1 NUMBER, field2 NUMBER);
CREATE TABLE table2(field1 NUMBER, field2 NUMBER);

INSERT INTO table1(field1, field2) VALUES(111, 121);
INSERT INTO table1(field1, field2) VALUES(112, 122);
INSERT INTO table1(field1, field2) VALUES(113, 123);
INSERT INTO table1(field1, field2) VALUES(114, 124);
INSERT INTO table1(field1, field2) VALUES(115, 125);

INSERT INTO table2(field1, field2) VALUES(111, 121);
INSERT INTO table2(field1, field2) VALUES(112, 122);
INSERT INTO table2(field1, field2) VALUES(213, 123);
INSERT INTO table2(field1, field2) VALUES(214, 124);
INSERT INTO table2(field1, field2) VALUES(215, 125);
COMMIT;

UPDATE  table1
SET     field1 = 1
WHERE   EXISTS
(
        SELECT  1
        FROM    table2
        WHERE   table1.field1 = table2.field1
        AND     table1.field2 = table2.field2
);
-- 2 rows updated.

SELECT * FROM table1;
/*
1   121
1   122
113 123
114 124
115 125
*/
于 2013-06-10T12:40:44.010 回答
0

如何检查更新是否有效？

如果您在另一个会话中查询该表，您将不会看到您的代码所做的任何更改，直到您在 pl/sql 代码之后执行提交语句。

于 2013-06-10T12:23:41.070 回答