我想更新当用户点击赞按钮时增加的赞数。就像在我的网站上一样,当用户在此页面 http://modelspk.com/urwa-tul-wusqa-model18 上单击“赞”按钮时,数据库中的赞数增加了 1。但是直到页面没有刷新,前端才更新。我目前使用的代码如下
<script type="text/javascript">
$("#likeThis").live("click", function () {
var pid = document.getElementById("pid");
var uRL = "/updateRatings.aspx?opt=1&pid=" + pid.value;
$.post(uRL);
alert('You Like This');
this.disabled = true;
document.getElementById("dislikeThis").disabled = true;
return false;
});
$("#dislikeThis").live("click", function () {
var pid = document.getElementById("pid");
var uRL = "/updateRatings.aspx?opt=2&pid=" + pid.value;
$.post(uRL);
alert("You don't Like This");
this.disabled = true;
document.getElementById("likeThis").disabled = true;
return false;
});
</script>
喜欢或不喜欢的html输入按钮如下..
<tr>
<td>
<asp:HiddenField ID="newPhotoID" runat="server" />
<input type="hidden" id="pid" value="<%=ModelID%>" />
<asp:Label ID="lblModelID" runat="server" Visible="false"></asp:Label>
<table width="253" align="center">
<tr>
<td align="left" class="txt" style="color: #0068c6; font-weight: bold;">
Rate This:
</td>
<td align="center" class="WaterText">
<input type="image" id="likeThis" onclick="javascript:rateThis(1,<%=ModelID%>);"
src="/images2/inact-thumb.jpg" onmouseover="this.src='/images2/active-thumb.jpg'"
onmouseout="this.src='/images2/inact-thumb.jpg'" /> <%=Likes%>
<span class="txt" style="color: #0068c6; font-weight: bold;">Likes</span>
</td>
<td align="center" class="WaterText">
<input type="image" id="dislikeThis" src="/images2/no-inact.jpg" onclick="javascript:rateThis(2,<%=ModelID%>)"
onmouseover="this.src='/images2/no-active.jpg'" onmouseout="this.src='/images2/no-inact.jpg'" /> <%=Dislikes%>
<span class="txt" style="color: #0068c6; font-weight: bold;">Disikes</span>
</td>
</tr>
</table>
</td>
<td width="127" align="right" class="WaterText">
<%=Views %>
<span class="txt" style="color: #0068c6; font-weight: bold;">Views</span>
</td>
</tr>
我想要做的是当用户点击like按钮时,它应该同时增加一个而不刷新页面。
问候:穆达西尔