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我在尝试让 JQuery.parseJSON 函数解析以下 JSON 时遇到问题。("Uncaught SyntaxError: Unexpected token")

[{"ExtIdremoto":"8","ExtNombre":"Silla bebe","ExtDescripcion":"Lorem ipsum lorem pete can","ExtPrecioDia":"4.5","ExtPrecio":"13.5","ExtCuantificable":"true"},{"ExtIdremoto":"9","ExtNombre":"Alzador","ExtDescripcion":"Lorem ipsum lorem pete can","ExtPrecioDia":"4.5","ExtPrecio":"13.5","ExtCuantificable":"false"},{"ExtIdremoto":"10","ExtNombre":"Maxicosi","ExtDescripcion":"Lorem ipsum lorem pete can\r\n•\tBlue\r\n•\tBlue\r\n•\t“blue”","ExtPrecioDia":"0","ExtPrecio":"0","ExtCuantificable":"true"},{"ExtIdremoto":"12","ExtNombre":"GPS","ExtDescripcion":"Lorem ipsum lorem pete can","ExtPrecioDia":"0","ExtPrecio":"0","ExtCuantificable":"true"}]

尽管 JSON 通过了http://jsonlint.com/验证，但看起来“•”是导致问题的原因。

我没有使用任何解析器库，我一直在尝试使用此处指定的函数来解决它： https ://stackoverflow.com/a/16652683/1161355

我怎样才能摆脱角色？

PD：我试图避免包含任何项目需求的外部库

更新

JSON 被存储到一个字符串中，并通过 session var 传递给 jsp。

StringBuilder sbJson = new StringBuilder();
sbJson.append("[");
Iterator<DatosExtra> it = datosDisponibilidad.getExtrasOpcionales().iterator();
while(it.hasNext()){
    DatosExtra datos = (DatosExtra) it.next();
    sbJson.append("{\"ExtIdremoto\":").append("\"").append(datos.getExtIdremoto()).append("\"").append(",\"ExtNombre\":").append(escaparCaracteresJSON(datos.getExtNombre(locale)))
                    .append(",\"ExtDescripcion\":").append(escaparCaracteresJSON(datos.getExtDescripcion(locale)))
                    .append(",\"ExtPrecioDia\":").append("\"").append(datos.getExtPrecioDia()).append("\"")
                    .append(",\"ExtPrecio\":").append("\"").append(datos.getExtPrecio()).append("\"")
                    .append(",\"ExtCuantificable\":").append("\"").append("S".equals(datos.getExtCuantificable())).append("\"")
                    .append("}");
    if(it.hasNext()) sbJson.append(",");
}
sbJson.append("]");
hpRequest.getRequest().getSession().setAttribute("jsonExtras", sbJson.toString());

其中 escaparCaracteresJSON 是注释的先前函数

在 JSP 中，我恢复了值：

var jsonExtras = jQuery.parseJSON('<%=session.getAttribute("jsonExtras")%>');

输出正是这个：

var jsonExtras = jQuery.parseJSON('[{"ExtIdremoto":"8","ExtNombre":"Silla bebe","ExtDescripcion":"Lorem ipsum lorem pete can","ExtPrecioDia":"4.5","ExtPrecio":"9","ExtCuantificable":"true"},{"ExtIdremoto":"9","ExtNombre":"Alzador","ExtDescripcion":"Lorem ipsum lorem pete can","ExtPrecioDia":"4.5","ExtPrecio":"9","ExtCuantificable":"false"},{"ExtIdremoto":"10","ExtNombre":"Maxicosi","ExtDescripcion":"Lorem ipsum lorem pete can\r\n•\tBlue\r\n•\tBlue\r\n•\t“blue”","ExtPrecioDia":"0","ExtPrecio":"0","ExtCuantificable":"true"},{"ExtIdremoto":"12","ExtNombre":"GPS","ExtDescripcion":"Lorem ipsum lorem pete can","ExtPrecioDia":"0","ExtPrecio":"0","ExtCuantificable":"true"}]');
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1 回答 1

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我相信您在\r,\n和\t- 它应该是\\r,\\n和中缺少一个反斜杠\\t。添加这些可以jQuery.parseJSON()正常工作 - http://jsfiddle.net/Nv282/。你能展示你如何在escaparCaracteresJSON()函数中转义字符吗？

于 2013-06-10T08:58:13.890 回答