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我正在尝试在 C 中标记一个字符串并使用 strtok_r 将标记保存到多个变量中。据我所知,我完全按照文档使用它:

char *saveptr;

char *ticketuser = strtok_r(request, ":", &saveptr);
char *ticketservice = strtok_r(NULL, ":", &saveptr);
char *ticketkey = strtok_r(NULL, ":", &saveptr);
//And so on...

其中 'request' 是一个以冒号分隔的标记字符串。当我尝试编译时,在我分配其中一个字符串的每一行上,我都会得到“赋值使指针从整数而不进行强制转换”。由于 strtok_r 应该返回一个 char*,所以我看不出问题出在哪里。

编辑:这是我的所有代码:

#include <stdio.h>

char *add( char *request ) {

  char *name = "add";
  char *secret = "secret1";
  char *failcode = "0:add:0";
  char returncode[80];
  char *saveptr;

  char *username = strtok_r(request, ":", &saveptr);
  char *servicename = strtok_r(NULL, ":", &saveptr);
  int parameter1 = atoi(strtok_r(NULL, ":", &saveptr));
  int parameter2 = atoi(strtok_r(NULL, ":", &saveptr));
  int ticketlead1 = atoi(strtok_r(NULL, ":", &saveptr));
  char *ticketuser = strtok_r(NULL, ":", &saveptr);
  char *ticketservice = strtok_r(NULL, ":", &saveptr);
  char *ticketkey = strtok_r(NULL, ":", &saveptr);

  //Catch any issues with the request
  if (strcmp(username,ticketuser) != 0){
    printf("username did not match ticket username\n");
    return failcode;
  }//if
  else if (strcmp(servicename,ticketservice) != 0){
    printf("service name did not match ticket service name\n");
    return failcode;
  }//else if
  else if (strcmp(secret,ticketkey) != 0){
    printf("secret key did not match ticket secret key\n");
    return failcode;
  }//else if

  //request was good, return value
  else{
    int val = parameter1 + parameter2;
    sprintf(returncode, "1:add:%d", val);
    return returncode;
  }//else

}//add


int main( int argc, char **argv ) {

  char *returned;
  char *req = "user:serv:5:8:1:user:serv:secret1";
  returned  = add(req);

  printf(returned);
  printf("\n");

  return 1;

}//main
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2 回答 2

10

在评论中找到了答案:我#include <string.h>在文件顶部丢失了。

编辑:我应该补充一点,除了上述问题之外,还有其他问题。首先,saveptr应该初始化为null。其次,正如 BLUEPIXY 指出的那样,returncode[]它是一个局部变量。将其定义替换为char *returncode = malloc ( . . . );

于 2013-06-10T01:20:33.983 回答
0

这可以通过在 C 中使用“string.h”头文件来删除

于 2014-08-15T03:51:08.750 回答